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3 years ago

13

What is the difference of 938.65−46.17?

2 answers:

AnnZ [28]3 years ago

5 0

892.48. Remember, when you subtract you always want the decimals to be right above/under each other.<span>

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Greeley [361]3 years ago

4 0

Look in the picture
i showed all the work

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Derek bought a package of 8 tennis balls. The total weight of the tennis balls was 18 ounces. How much did each tennis ball weig

beks73 [17]

2.25 ounces...18/8=2.25

7 0

2 years ago

Shilpa can stitch a shirt in 5 hours while Alka can do it in 4 hours how much time would it take to stitch 36 shirts if they wor

scoundrel [369]

Answer:

together, they would stitch 36 shirts in 162 hours or 6 days and 18 hours

8 0

2 years ago

D= kA [T2 - T1 / L] Solve for T1

mel-nik [20]

$d=\dfrac{k_A(T_2-T_1)}{T}\ \ \ \ |multiply\ both\ sides\ by\ T\\\\k_A(T_2-T_1)=dT\ \ \ \ |divide\ both\ sides\ by\ k_A\\\\T_2-T_1=\dfrac{dT}{k_A}\ \ \ \ |subtract\ T_2\ from\ both\ sides\\\\-T_1=\dfrac{dT}{k_A}-T_2\ \ \ \ \ |change\ signs\\\\\boxed{T_1=T_2-\frac{dT}{k_A}}$

5 0

2 years ago

A student S is suspected of cheating on exam, due to evidence E of cheating being present. Suppose that in the case of a cheatin

Kay [80]

Answer:

Step-by-step explanation:

Suppose we think of an alphabet X to be the Event of the evidence.

Also, if Y be the Event of cheating; &

Y' be the Event of not involved in cheating

From the given information:

$P(\dfrac{X}{Y}) = 60\% = 0.6$

$P(\dfrac{X}{Y'}) = 0.01\% = 0.0001$

$P(Y) = 0.01$

Thus, $P(Y') \ will\ be = 1 - P(Y)$

P(Y') = 1 - 0.01

P(Y') = 0.99

The probability of cheating & the evidence is present is = P(YX)

$P(YX) = P(\dfrac{X}{Y}) \ P(Y)$

$P(YX) =0.6 \times 0.01$

$P(YX) =0.006$

The probabilities of not involved in cheating & the evidence are present is:

$P(Y'X) = P(Y') \times P(\dfrac{X}{Y'})$

$P(Y'X) = 0.99 \times 0.0001 \\ \\ P(Y'X) = 0.000099$

(b)

The required probability that the evidence is present is:

P(YX or Y'X) = 0.006 + 0.000099

P(YX or Y'X) = 0.006099

(c)

The required probability that (S) cheat provided the evidence being present is:

Using Bayes Theorem

$P(\dfrac{Y}{X}) = \dfrac{P(YX)}{P(Y)}$

$P(\dfrac{Y}{X}) = \dfrac{P(0.006)}{P(0.006099)}$

$P(\dfrac{Y}{X}) = 0.9838$

5 0

2 years ago

2800 ml +2.6 L<br> 2800 ml +2.6 L

Tom [10]

Answer:

10 800 ml

Step-by-step explanation:

I hope this helps :}

5 0

3 years ago