The answer to this query is AA similarity postulate. <span>
<span>Because the triangles given are only similar in angle but
dissimilar in sides which makes it incongruent with respect to the sides, AA
similarity postulate is the exact answer.
SAS ASA are not possible answers. </span></span>
You can use the identity
cos(x)² +sin(x)² = 1
to find sin(x) from cos(x) or vice versa.
(1/4)² +sin(x)² = 1
sin(x)² = 1 - 1/16
sin(x) = ±(√15)/4
Then the tangent can be computed as the ratio of sine to cosine.
tan(x) = sin(x)/cos(x) = (±(√15)/4)/(1/4)
tan(x) = ±√15
There are two possible answers.
In the first quadrant:
sin(x) = (√15)/4
tan(x) = √15
In the fourth quadrant:
sin(x) = -(√15)/4
tan(x) = -√15
Answer:
Step 1: Transpose everything to one side
12. x²+16x+15-10x+4=0
Step 2: Add the like terms
x² + (16x - 10x) + 15 + 4=0
x² + 6x + 19=0
Step 3: Use the quadratic formula to get the value(s) of x.
a=1 b=6 c=19
therefore, x=... or x
Answer:
97km/h to 1dp
Step-by-step explanation:
47mins is 0.783 of an hour
76km/0.783 = 97.0212km/h
