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yKpoI14uk [10]
3 years ago
6

Please I need help and I dont get it..

Mathematics
1 answer:
svp [43]3 years ago
6 0
For the last question

40*3=120 total cakes
120*.15=18 chocolate cakes
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meriva
16 2/3

you just need to multiply 4 1/6 by 4
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3 years ago
Help D: log3 x^6 =12 <br>find x
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8 0
3 years ago
MATH <br> can somebody help me with these questions?
Dmitriy789 [7]
I’m learning this in class as well
Ok so basically you just need to find 2 random points so like (30,100) and (20,30)
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6 0
2 years ago
Find an equation of a line that is tangent to the graph of f and parallel to the given line. Please see picture
ivanzaharov [21]

Answer:

y = 3x - 2 (smaller y-intercept)

y = 3x + 2 (larger y-intercept)

Step-by-step explanation:

First let's write the generic equation of a line:

y = ax + b

This line needs to be parallel to the line 3x - y + 5 = 0, so it needs to have the same slope of this line.

The line 3x - y + 5 = 0 has a slope of 3, so our line has a = 3:

y = 3x + b

Now we need to find the values of b that make this line tangent to the function f(x) = x^3

Let's first find the derivative of f(x) in relation to x:

df(x)/dx = 3x^2

This derivative is the slope of the tangent line to the function for any value of x. We need a slope of 3, so:

3x^2 = 3

x^2 = 1

x = ±1

Now, to find the y-values, we have:

f(1) = 1^3 = 1

f(-1) = (-1)^3 = -1

So, using the points (1,1) and (-1,-1) in our parallel line, we have:

first line using (1,1) : 1 = 3*1 + b

b = -2

second line using (-1,-1) : -1 = -3*1 + b

b = 2

The value of b is the y-intercept of the line, so the line with smaller y-intercept is y = 3x - 2, and the line with larger y-intercept is y = 3x + 2

8 0
2 years ago
I’m not sure how to do this problem
strojnjashka [21]
The first one would be x^12
6 0
3 years ago
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