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3 years ago

Help me Guess just help pleaseeeee

Mathematics

2 answers:

Diano4ka-milaya [45]3 years ago

8 0

Answer:

A, and D are the asnwers

Arisa [49]3 years ago

7 0

Answer:

Probaly Rational number

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I need help with this question

Helga [31]

Answer:

Math-way helps with algebra, hope you find the answer!

Step-by-step explanation:

7 0

3 years ago

Alaska has a land area of about 1,700,000 square kilometers Florida has a land area 1/10 the size of Alaska.what is the land are

Virty [35]

1700000/10 is 170000
So the size of Florida is 170,000 $kilometers^{2}$

5 0

3 years ago

Separate the x- and y-values with a comma. X=-3+y 26x - 5y = 6

labwork [276]

Answer:

The solution of the given system is (x,y) = (1,4)

Step-by-step explanation:

Here, the given system of equation is:

x = -3 + y

26 x - 5 y = 6

Now, substitute x = -3 + y in the second equation , we get

26 x - 5 y = 6 ⇒ 26 (-3 + y) - 5 y = 6

or, 26(-3) + 26(y) - 5y = 6

⇒ - 78 + 26 y - 5y = 6

⇒ 21 y = 84

⇒ y = 84 / 21 = 4 or , y = 4

So x = -3 + y = -3 + 4 = 1

Hence, the solution of the given system is (x,y) = (1,4)

5 0

3 years ago

Find a function where f(0)=2 and f(1)=2

xenn [34]

Answer:

Do you want to be extremely boring?

Since the value is 2 at both 0 and 1, why not make it so the value is 2 everywhere else?

$f(x) = 2$ is a valid solution.

Want something more fun? Why not a parabola? $f(x)= ax^2+bx+c$ .

At this point you have three parameters to play with, and from the fact that $f(0)=2$ we can already fix one of them, in particular $c=2$ . At this point I would recommend picking an easy value for one of the two, let's say $a= 1$ (or even $a=-1$ , it will just flip everything upside down) and find out b accordingly: $f(1)=2 \rightarrow 1^2+b+2=2 \rightarrow b=-1$

Our function becomes

$f(x) = x^2-x+2$

Notice that it works even by switching sign in the first two terms: $f(x) = -x^2+x+2$

Want something even more creative? Try playing with a cosine tweaking it's amplitude and frequency so that it's period goes to 1 and it's amplitude gets to 2: $f(x) = A cos (kx)$

Since cosine is bound between -1 and 1, in order to reach the maximum at 2 we need $A= 2$ , and at that point the first condition is guaranteed; using the second to find k we get $2= 2 cos (k1) = cos k = 1 \rightarrow k = 2\pi$