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Lelu [443]
3 years ago
10

The midpoint of line AC is

Mathematics
1 answer:
Maurinko [17]3 years ago
5 0

Step-by-step explanation:

Hey there!

Given;

Midpoint is (-1,3) and one endppint is; A(4,-1).

Let the coordinates of C be (x,y).

<u>Use</u><u> </u><u>the</u><u> </u><u>midpoint</u><u> </u><u>formula</u><u>.</u>

<u>(x,y) = ( \frac{x1 + x2}{2} ,\frac{y1 + y2}{2} )</u>

<u>Put</u><u> </u><u>all values</u><u>. </u>

<u>( - 1,3) =  (\frac{4 + x}{2} ,\frac{ - 1 + y}{2} )</u>

Since, they are equal, equating with their corresponding elements we get,

- 1 =  \frac{4 + x}{2}

<u>Simplify</u><u> </u><u>it</u><u>. </u>

<u>- 2 = 4 + x</u>

<u>x =  - 6</u>

<u>Again</u><u>,</u>

<u>3 =  \frac{ - 1 + y}{2}</u>

<u>Simplify</u><u> </u><u>it</u><u>. </u>

<u>6 =  - 1 + y</u>

<u>y = 7</u>

<u>Therefore the</u><u> </u><u>another</u><u> </u><u>endpoint is</u><u> </u><u>C</u><u>(</u><u>-6</u><u>,</u><u>7</u><u>)</u><u>.</u>

<em><u>Hope it helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>

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