Question

The midpoint of line AC is

Answer 1

Step-by-step explanation:

Hey there!

Given;

Midpoint is (-1,3) and one endppint is; A(4,-1).

Let the coordinates of C be (x,y).

Use the midpoint formula.

$(x,y) = ( \frac{x1 + x2}{2} ,\frac{y1 + y2}{2} )$

Put all values.

$( - 1,3) = (\frac{4 + x}{2} ,\frac{ - 1 + y}{2} )$

Since, they are equal, equating with their corresponding elements we get,

$- 1 = \frac{4 + x}{2}$

Simplify it.

$- 2 = 4 + x$

$x = - 6$

Again,

$3 = \frac{ - 1 + y}{2}$

Simplify it.

$6 = - 1 + y$

$y = 7$

Therefore the another endpoint is C(-6,7).

Hope it helps...