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Talja [164]
3 years ago
10

Solve this question in the following photo​

Mathematics
1 answer:
katovenus [111]3 years ago
6 0

Answer:

55/43

Step-by-step explanation:

(x/y) = 7/3, (x^2/y^2)=49/9, multiply by 3 above and multiply 2 below, 3x^2/2y^2=147/18. Next apply C&D and you will get (3x^2+2y^2)/(3x^2-2y^2)=(147+18)/(147-18)=165/129=55/43

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Can the sides of a right triangle have the lengths 5 15 and 250. explain​
Llana [10]

Answer:

yes

Step-by-step explanation:

Theorem gives us a2 + b2 = c2 for a right triangle, where c is the hypotenuse and a and b are the smaller sides. Here a is equal to 5 and c is equal to 14, so b2 = 142 – 52 = 171. Therefore b is equal to the square root of 171 or approximately 13.07.

8 0
3 years ago
NEED ANSWER QUICKLY
Hitman42 [59]
It’s between two and three which might turn out to be a decimal
8 0
3 years ago
A sculpture of a gaint cube contains 1000 cubes within it. How many smaller cubes are along each edge of the sculpture
uranmaximum [27]

<u>ANSWER: </u>

A sculpture of a giant cube contains 1000 cubes within it .Along side of each edge of a giant cube there are 10 small cubes.

<u>SOLUTION</u>:  

Given that a giant cube has 1000 cubes in it.

Let , length of the giant cube be L

Length of each small cube be v

Then, volume of giant cube = \mathrm{L}^{3}

Volume of small cube = v^{3}

According to the given problem, Volume of giant cube must be equal to 1000 small cubes volume.

\mathrm{L}^{3}=1000 \mathrm{v}^{3}

Apply cube root on both sides

\sqrt[3]{L^{3}}=\sqrt[3]{1000 \times v^{3}}

\sqrt[3]{L^{3}}=\sqrt[3]{(10 v)^{3}}

\sqrt[3]{L^{3}} = \sqrt[3]{(10 v)^{3}}

\mathrm{L}=10v

From above equation we can say that along side of each edge of a giant cube there are 10 small cubes.

8 0
4 years ago
Help with 43 show work for this please!!
nexus9112 [7]
S = 150m

This is because per month, m, they earn 150 dollars, and thus, the total, s, would be 150 times the months.
7 0
3 years ago
I WILL GIVE BRAINLIEST, PLS HELP-A farmer has 300 ft of fencing with which to enclose a rectangular pen next to a barn. The barn
hjlf
The maximum area is the area that uses half the fence (150 ft) for the side parallel to the barn and the other half for the ends of the pen (75 ft each). That area is 11,250 ft^2.
4 0
3 years ago
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