2 years ago

Solve this question in the following photo

Mathematics

1 answer:

katovenus [111]2 years ago

6 0

Answer:

55/43

Step-by-step explanation:

(x/y) = 7/3, (x^2/y^2)=49/9, multiply by 3 above and multiply 2 below, 3x^2/2y^2=147/18. Next apply C&D and you will get (3x^2+2y^2)/(3x^2-2y^2)=(147+18)/(147-18)=165/129=55/43

You might be interested in

Please help with 17, 19, and 21 using trigonometry. Thanks!

omeli [17]

I honestly don’t know. But the square in the bottom of the triangles indicate that it is a right triangle equaling 90 degrees. You can try using that along with other knowledge of right triangles you have. Could you possibly use Pythagorean theorem also?

7 0

2 years ago

Compare the weather on two different days using an inequality. Then see if their comparisons change by finding the absolute valu

dusya [7]

Inequalities are used to compare unequal expressions.

The actual comparison is: $\mathbf{-3.5 < 5}$ or $\mathbf{5 > -3.5}$