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pishuonlain [190]
4 years ago
12

Which is the factorization of 8x2 + 13x – 6?

Mathematics
1 answer:
sleet_krkn [62]4 years ago
6 0
I hope this helps you

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write an equation of the line passing through point p that is perpendicular to the given line p(6,10),y=-3x+13
patriot [66]

Answer:

y = \frac{1}{3} x + 8

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y-intercept )

y = - 3x + 13 is in this form

with m = - 3

Given a line with slope m then the slope of a line perpendicular to it is

m_{perpendicular} = - \frac{1}{m} = - \frac{1}{-3} = \frac{1}{3}

y = \frac{1}{3} x + c ← is the partial equation

To find c substitute (6, 10) into the partial equation

10 = 2 + c ⇒ c = 10 - 2 = 8

y = \frac{1}{3} x + 8 ← equation of line


6 0
3 years ago
In circle A as shown below, segment DC is tangent to circle A at D.
Likurg_2 [28]

Answer:

AB = 3

Step-by-step explanation:

AB = AD

AB² + 4² = (AB + 2)²

AB² + 16 = AB² + 4AB + 4

combine like terms:

4AB = 12

AB = 3

4 0
3 years ago
Read 2 more answers
The triangle on the grid will be translated two units left. On a coordinate plane, triangle A B C has points (negative 1, negati
nignag [31]

Answer:

Option B.

Step-by-step explanation:

The given vertices of triangle ABC are (-1, -1), (-1, -5) and (0.5, -5).

We need to find the coordinates of triangle when it is translated two units left.

So, the rule of translation is

(x,y)\rightarrow (x-2,y)

Using this rule, we get

A(-1,-1)\rightarrow A'(-1-2,-1)=A'(-3,-1)

B(-1,-5)\rightarrow B'(-1-2,-5)=B'(-3,-5)

C(0.5,-5)\rightarrow C'(0.5-2,-5)=C'(-1.5,-5)

The vertices of triangle A'B'C' are A'(-3,-1), B'(-3,-5) and C'(-1.5,-5).

Therefore, the correct option is B.

8 0
3 years ago
Read 2 more answers
Can anyone help me with this question?
joja [24]

Answer:

The answer is D, or 5/7

4 0
3 years ago
Read 2 more answers
Battery packs in electric go-carts need to last a fairly long time. The run-times (time until it needs to be recharged) of the b
pav-90 [236]

Answer:

The minimum level for which the battery pack will be classified as highly sought-after class is 2.42 hours

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 2, \sigma = 0.33

What is the minimum level for which the battery pack will be classified as highly sought-after class

At least the 100-10 = 90th percentile, which is the value of X when Z has a pvalue of 0.9. So it is X when Z = 1.28.

Z = \frac{X - \mu}{\sigma}

1.28 = \frac{X - 2}{0.33}

X - 2 = 0.33*1.28

X = 2.42

The minimum level for which the battery pack will be classified as highly sought-after class is 2.42 hours

4 0
3 years ago
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