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4 years ago

Which accurately describes the behavior of sound and light in the vacuum of space?

2 answers:

8 0

<span>
A vacuum doesn't contain a medium. Light, which is an electromagnetic
wave and doesn't require a medium, will travel there. Sound, which is a
mechanical wave and requires a medium, will not travel there.</span>

(You can see the light of the sun and other stars, which travels to us through
space. Astronauts can't hear the sound of each others' voices when they're
standing together on the moon because there's no medium between them,
so they have to use radio even to go only a few feet.)

MrRissso [65]4 years ago

4 0

Answer: A Medium is not necessary

Is C

Explanation: In contrast, light waves <em>CAN </em>travel through a vacuum, and do not require a medium. In empty space, the wave does not dissipate grow smaller no matter how far it travels, because the wave is not interacting with anything else. However, light can also travel within some materials, like glass and water.

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The gravitational force between two objects that are 2.1 times 10^-1 m apart is 3.2 times 10^-6 N. If the mass of one object is

Shtirlitz [24]

Answer:

Mass of the other object is 38.45 kg.

Explanation:

Given:

The gravitational force between two objects is, $F=3.2\times 10^{-6}$ N

Mass of one object is, $m_{1}=55\ kg$

Distance between the objects is, $r=2.1\times 10^{-1}\ m$

Gravitational constant is, $G =6.674\times 10^{-11}\ m^3 kg^{-1}s^{-2}$

Let the mass of the other object be $m_{2}\ kg$

Gravitational force is given as:

$F=\frac{Gm_1m_2}{r^2}$

Plug in the given values and solve for $m_2$ . This gives,

$3.2\times 10^{-6}=\frac{6.674\times 10^{-11}\times 55\times m_2}{(2.1\times 10^{-1})^2}\\3.2\times 10^{-6}=\frac{6.674\times 10^{-11}\times 55\times m_2}{0.0441}\\3.2\times 10^{-6}=8.3236\times 10^{-8}m_2\\m_2=\frac{3.2\times 10^{-6}}{8.3236\times 10^{-8}}= 38.45\ kg$

Therefore, the mass of the other object is 38.45 kg.

3 0

4 years ago

Three cars, car x, car y, and car z, begin accelerating from rest, at the same time. car x is more massive than car y, which is

grigory [225]

When the net force exerted on each car is identical. after 10 seconds, the amount of momentum is same for all cars.

<h3>What is impulse?</h3>

The change in momentum is equal to the product of impact force applied while colliding and time for that impact.

F. t = m (Vf -Vi)

where, Vf is the final velocity and Vi is the initial velocity.

For car X, Fx x t = Mx Vx

For car Y, Fy x t = My Vy

For car Z, Fz x t = Mz Vz

The force applied is same for all and the the time is also same equal to 10 seconds. The impulse is same for all the cars.

Thus, the three cars have same momentum.

Learn more about impulse.

brainly.com/question/16980676

#SPJ1

6 0

2 years ago

How much heat is needed to boil 5.30 kg of water at its boiling point?

vivado [14]

Answer:

Required heat Q = 11,978 KJ

Explanation:

Given:

Mass = 5.3 kg

Latent heat of vaporization of water = 2,260 KJ / KG

Find:

Required heat Q

Computation:

Required heat Q = Mass x Latent heat of vaporization of water

Required heat Q = 5.3 x 2260

Required heat Q = 11,978 KJ

Required heat Q = 12,000 KJ (Approx.)

4 0

3 years ago

Read 2 more answers

To find the number of neutrons in an atom, you would subtract

larisa86 [58]

To find the number of neutrons in an atom, what we must do is to follow the following steps:

1) Find the element in the periodic table.

2) Find the atomic number of the element. The atomic number is the number of protons of a single atom of that element.

3) Find the atomic weight of the element.

4) Finally, we look for the number of neutrons. For this, we follow the following relationship:

Atomic weight - number of protons = number of neutrons.

Answer:

To find the number of neutrons in an atom, you would subtract:

B.) atomic number from mass number

7 0

3 years ago

Read 2 more answers

An electromagnetic wave in a vacuum has a wavelength of 0.032 m. What is its frequency?

Sergio [31]

L=wavelength
L=0.032
c=Lf
f=c/L
f=3e8/0.032
f=9.375GHz

7 0

3 years ago