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OverLord2011 [107]
2 years ago
14

Three cars, car x, car y, and car z, begin accelerating from rest, at the same time. car x is more massive than car y, which is

more massive than car z. the net force exerted on each car is identical. after 10 seconds, which car has the most amount of momentum?
Physics
1 answer:
grigory [225]2 years ago
6 0

When the net force exerted on each car is identical. after 10 seconds, the amount of momentum is same for all cars.

<h3>What is impulse?</h3>

The change in momentum is equal to the product of impact force applied while colliding and time for that impact.

F. t = m (Vf -Vi)

where, Vf is the final velocity and Vi is the initial velocity.

For car X, Fx x t = Mx Vx

For car Y, Fy x t = My Vy

For car Z, Fz x t = Mz Vz

The force applied is same for all and the the time is also same equal to 10 seconds. The impulse is same for all the cars.

Thus, the three cars have same momentum.

Learn more about impulse.

brainly.com/question/16980676

#SPJ1

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A concrete block is hung from an ideal spring that has a force constant of 100 N/m . The spring stretches 0.129 m .A- What is th
madam [21]

Answer:

1.31498 kg

0.72050 s

0.72050 s

Explanation:

m = Mass of block

g = Acceleration due to gravity = 9.81 m/s²

k = Spring constant = 100 N/M

x = Displacement = 0.129 m

The force balance is

mg=kx\\\Rightarrow m=\dfrac{kx}{g}\\\Rightarrow m=\dfrac{100\times 0.129}{9.81}\\\Rightarrow m=1.31498\ kg

The mass of the block is 1.31498 kg

Time period is given by

T=2\pi\sqrt{\dfrac{m}{k}}\\\Rightarrow T=2\pi\sqrt{\dfrac{1.31498}{100}}\\\Rightarrow T=0.72050\ s

The period of oscillations is 0.72050 s

The time period does not depend on the acceleration due to gravity. It varies with the mass and the spring constant.

Hence, the time period would be the same

8 0
3 years ago
What is the magnitude of the linear momentum of a 7.30 kg bowling ball going down the
padilas [110]
Momentum = mass x velocity
m=7.3kg
v=20 m/s

momentum= 7.3(20) = 146 kg m/s
3 0
3 years ago
Which of the following is not an example of kinetic energy being converted to potential energy?
KengaRu [80]

The list of choices you provided with your question
is utterly devoid of any such examples.

6 0
3 years ago
Read 2 more answers
Which statement explains how it is possible to carry books to school without changing the kinetic or potential energy of the boo
Mamont248 [21]

Answer:

a. by moving the book without acceleration and keeping the height of the book constant

Explanation:

FOR CONSTANT KINETIC ENERGY:

The kinetic energy of a body depends upon its speed according to its formula:

ΔK.E = (1/2)mΔv²

So, for Δv = 0 m/s

ΔK.E = 0 J

So, for keeping kinetic energy constant, the books must be moved at constant speed without acceleration.

FOR CONSTANT POTENTIAL ENERGY:

The potential energy of a body depends upon its height according to its formula:

ΔP.E = mgΔh

So, for Δh = 0 m/s

ΔP.E = 0 J

So, for keeping potential energy constant, the books must be moved at constant height.

So, the correct option is:

<u>a. by moving the book without acceleration and keeping the height of the book constant</u>

8 0
3 years ago
A government agency estimated that air bags have saved over 14,000 lives as of April 2004 in the United States. (They also state
balu736 [363]

To solve this problem it is necessary to apply the concepts related to momentum, momentum and Force. Mathematically the Impulse can be described as

I = F*t

Where,

F= Force

t= time

At the same time the moment can be described as a function of mass and velocity, that is

P = m\Delta v \rightarrow P=m(v_1-v_2)

Where,

m = mass

v = Velocity

From equilibrium the impulse is equal to the momentum, therefore

I = p

Ft = m(v_1-v_2)

PART A) Since the body ends at rest, we have the final speed is zero, so the momentum would be

p=m(v_1-v_2)

p = 75*0.15

p = 1125Kg\cdot m/s

Therefore the magnitude of the person's impulse is 1125Kg.m/s

PART B) From the equation obtained previously we have that the Force would be:

Ft = m(v_1-v_2)

F(0.025)= 1125

F= 45000N

Therefore the magnitude of the average force the airbag exerts on the person is 45000N

6 0
3 years ago
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