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OverLord2011 [107]
2 years ago
14

Three cars, car x, car y, and car z, begin accelerating from rest, at the same time. car x is more massive than car y, which is

more massive than car z. the net force exerted on each car is identical. after 10 seconds, which car has the most amount of momentum?
Physics
1 answer:
grigory [225]2 years ago
6 0

When the net force exerted on each car is identical. after 10 seconds, the amount of momentum is same for all cars.

<h3>What is impulse?</h3>

The change in momentum is equal to the product of impact force applied while colliding and time for that impact.

F. t = m (Vf -Vi)

where, Vf is the final velocity and Vi is the initial velocity.

For car X, Fx x t = Mx Vx

For car Y, Fy x t = My Vy

For car Z, Fz x t = Mz Vz

The force applied is same for all and the the time is also same equal to 10 seconds. The impulse is same for all the cars.

Thus, the three cars have same momentum.

Learn more about impulse.

brainly.com/question/16980676

#SPJ1

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You are given a copper bar of dimensions 3 cm × 5 cm × 8 cm and asked to attach leads to it in order to make a resistor. If you
Nataliya [291]

Answer:

Option B is correct.

The leads should be attached to the opposite faces that measure 3 cm × 5 cm to obtain the maximum possible resistance.

Explanation:

The resistance of a material is given by

R = (ρL)/A

where ρ = resistivity of the material

A = Cross sectional Area through which current would flow

L = length of the material.

From the relation, it is evident that the resistance of a material is directly proportional to its length and inversely proportional to its cross sectional Area.

As the length of material increases, the resistance of the material also increases, and a decreasing length translates to a decreasing resistance too. (Direct Proportionality)

And as the cross sectional Area of the material increases, the resistance of the material decreases. Decrease in cross sectional Area of the material translates to an increase in resistance. (Inverse Proportionality)

To maximize resistance of a material, it would make sense to maximize the length and minimize the cross sectional Area of that material. (Since resistivity is assumed to be constant)

And with a dimension of (3 × 5 × 8), the longest length is 8 cm and the smallest cross sectional Area is (3 × 5).

So, the leads should be atrached to the face with area (3 cm × 5 cm), which is the smallest cross sectional Area and gives the largest length between the faces (8 cm).

This subsequently maximizes the resistance.

Hope this Helps!!!

4 0
3 years ago
Read 2 more answers
Bats use sound to sense objects by sending out short ultrasound pulses and listening for the echo off the object. A. Sketch the
ivann1987 [24]

Answer:

B. t = 0.250s

Explanation:

A. An image with the sketch of the bat emitting a sound, which reflects on a surface and return to the bat is attached below.

B. In order to calculate the time that the pulse emitted by the bat, return to the bat, you first calculate the time that pulse takes to arrive to the object.

You use the following formula:

x=vt      (1)

x: distance to the object = 43m

t: time = ?

v: speed of sound beat = 343 m/s  

You solve the equation (1) for t:

t=\frac{x}{v}=\frac{43m}{343m/s}=0.125s

The time on which the bat hears the echo is twice the value of t, that is:

t'=2(0.125s)=0.250s

The time on which bat heart the echo of its sound, from the moment on which bat emitted it, is 0.250s

6 0
3 years ago
What is the wavelength of an earthquake wave if it has a speed of 4 km/s and a frequency of 7 Hz?
damaskus [11]

Answer: 0.571 km/s

λ = v/f

λ = 4/7

λ = 0.571 km/s


7 0
4 years ago
A 10 µf capacitor is charged to 108 v and is then connected across a 328 ω resistor. what is the initial charge on the capacitor
valina [46]
The capacitance is defined as the maximum charge stored in a capacitor, Q, divided by the voltage applied, V:
C= \frac{Q}{V}

The capacitor is initially charged with the battery of 108 V, so the the initial charge on the capacitor can be found by re-arranging the previous formula:
Q=CV=(10 \mu F)(108 V)=1080 \mu C
8 0
4 years ago
A 90-kg astronaut is stranded in space at a point 6.0 m from his spaceship, and he needs to get back in 4.0 min to control the s
Stella [2.4K]

Momentum = 0.5 * 4 = 2 
to conclude the man’s velocity after he throws the piece of equipment, divide this number by the man’s mass. 

v = 2/90 

This is about 0.0222 m/s. To know if he can move 6 meters at velocity in 4minutes, use the following equation. 

d = v * t, t = 4 * 60 = 240 s 
d = 2/90 * 240 = 5⅓ meters. 

This is ⅔ of a meter from the spaceship. To know the velocity that he must have to move 6 meter, use the same equation. 

6 = v * 240 
v = 6/240 
This is about 0.00416 m/s. 
His final momentum = 90 * 6/240 = 2.25 


To know the velocity of the package, divide this number by the mass of the package. 
v = 2.25/0.5 = 4.5 m/s

8 0
3 years ago
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