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alexandr402 [8]
4 years ago
12

a bear has a mass of 500kg and 100,000 J of mechanical kinetic energy. what is the speed of the bear?

Physics
1 answer:
3241004551 [841]4 years ago
7 0

Answer: v = 20 m/s

Explanation: Solution:

Use the formula of Kinetic Energy and derive for v:

KE = 1/2 mv²

To find v:

v = √ 2 KE / m

  = √ 2 ( 100000 J ) / 500 kg

  = √ 400 m/s

  = 20 m/s

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A coil 3.85 cm radius, containing 450 turns, is placed in a uniform magnetic field that varies with time according to B=( 1.20×1
Nimfa-mama [501]

Answer:

0.025V + (0.000218V/s³) t³

Explanation:

Parameters given:

Radius of coil, r = 3.85 cm = 0.0385 m

Number of turns, N = 450

Magnetic field, B = ( 1.20×10^(−2) T/s )t + (2.60×10^(−5) T/s4 )t^4.

The magnitude of Induced EMF is given as:

E = N * A * dB/dt

Where A is the area of the coil

First, we differentiate the magnetic field with respect to time:

dB/dt = 0.012 + 0.000104t³

Therefore, EMF will be:

E = 450 * 3.142 * (0.012 + 0.000104t³)

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E = 0.025V + (0.000218V/s³)t³

6 0
3 years ago
Read 2 more answers
2000, the Millennium Bridge, a new footbridge over the River Thames in London, England, was opened to the public. However, after
sweet [91]

Answer:

n = 1810

A = 25 mm

Explanation:

Given:

Lateral force amplitude, F = 25 N

Frequency, f = 1 Hz

mass of the bridge, m = 2000 kg/m

Span, L = 144 m

Amplitude of the oscillation, A = 75 mm = 0.075 m

time, t = 6T

now,

Amplitude as a function of time is given as:

A(t)=A_oe^{\frac{-bt}{2m}}

or amplitude for unforce oscillation

\frac{A_o}{e}=A_oe^{\frac{-b(6T)}{2m}}

or

\frac{6bt}{2m}=1

or

b=\frac{m}{3T}

Now, provided in the question Amplitude of the driven oscillation

A=\frac{F_{max}}{\sqrt{(k-m\omega_d^2)+(b\omega_d^2)}}

the value of the maximum amplitude is obtained (k=m\omega_d^2)

thus,

A=\frac{F_{max}}{(b\omega_d}

Now, for n people on the bridge

Fmax = nF

thus,

max amplitude

0.075=\frac{nF}{((\frac{m}{3T})2\pi}

or

n = 1810

hence, there were 1810 people on the bridge

b)A=\frac{F_{max}}{(b\omega_d}

since the effect of damping in the millenium bridge is 3 times

thus,

b=3b

therefore,

A=\frac{F_{max}}{(3b\omega_d}

or

A=\frac{1}{(3}A_o

or

A=\frac{1}{(3}0.075

or

A = 0.025 m = 25 mm

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Answer:

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