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Molodets [167]
3 years ago
14

Distance between two points (-5,5) and ( 3,-3)

Mathematics
1 answer:
stiks02 [169]3 years ago
7 0

Answer:

8\sqrt{2}

Step-by-step explanation:

Using the pythagorean theorem, you can find that the distance between the two points is \sqrt{(3-(-5))^2+(5-(-3))^2}=\sqrt{128}=8\sqrt{2}. Hope this helps!

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What is the equation of the line that passes through <br><br> (−3,5) and has a slope of<br> −2?
Tatiana [17]

Answer:

y-5=-2(x+3)

Step-by-step explanation:

y-y1=m(x-x1)

m=-2

y-5=-2(x-(-3))

y-5=-2(x+3)

5 0
3 years ago
Ten college students were randomly selected. Their grade point averages​ (GPAs) when they entered the program were between 3.5 a
solong [7]

Answer:

The 95% confidence interval for the true slope is (0.03985, 0.14206).

Step-by-step explanation:

For the regression equation:

\hat y=\alpha +\hat \beta x

The (1 - <em>α</em>)% confidence interval for the regression coefficient or slope (\hat \beta ) is:

Ci=\hat \beta \pm t_{\alpha/2, (n-2)}\times SE(\hat \beta )

The regression equation for current GPA (Y) of students based on their GPA's when entering the program (X) is:

\hat Y=3.584756+0.090953 X

The summary of the regression analysis is:

Predictor          Coefficient             SE             t-stat            p-value

Constant             3.584756          0.078183       45.85075      5.66 x 10⁻¹¹

Entering GPA   0.090953          0.022162        4.103932       0.003419

The regression coefficient and standard error are:

\hat \beta = 0.090953\\SE (\hat \beta)=0.022162

The critical value of <em>t</em>  for 95% confidence level and 8 degrees of freedom is:

t_{\alpha/2, n-2}=t_{0.05/2, 10-2}=t_{0.025, 8}=2.306

Compute the 95% confidence interval for (\hat \beta ) as follows:

CI=\hat \beta \pm t_{\alpha/2, (n-2)}\times SE(\hat \beta )\\=0.090953\pm 2.306\times 0.022162\\=0.090953\pm 0.051105572\\=(0.039847428, 0.142058572)\\\approx (0.03985, 0.14206)

Thus, the 95% confidence interval for the true slope is (0.03985, 0.14206).

6 0
3 years ago
Area of the lawn? Please
Lesechka [4]

Answer:

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Step-by-step explanation:

5 0
3 years ago
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Find an equation of variation in which y varies jointly as x and z and inversely as the product of w and​ p, where yequalsstartf
leva [86]

To solve this problem you must apply the proccedure shown below:

1. You have that y varies jointly as x and z and inversely as the product of w and​ p. Therefore, you can write the following equation, where k is the constant of proportionality:

y=k(\frac{xz}{wp} )

2. Now, you must solve for the constant of proportionality, as following:

k=\frac{ywp}{xz}

3. Susbtiute values:

y=\frac{7}{28} \\ x=7\\ z=4\\ w=7\\ p=8

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The answer is: y=0.5(\frac{xz}{wp})

7 0
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Number 16, he put 1/2 of his money into his savings and took the rest to spend. So fraction of his amusement park money he spent on rides and popcorn is (1/5 + 3/4) x 1/2 = 19/40 <=> A

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