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Molodets [167]
4 years ago
14

Distance between two points (-5,5) and ( 3,-3)

Mathematics
1 answer:
stiks02 [169]4 years ago
7 0

Answer:

8\sqrt{2}

Step-by-step explanation:

Using the pythagorean theorem, you can find that the distance between the two points is \sqrt{(3-(-5))^2+(5-(-3))^2}=\sqrt{128}=8\sqrt{2}. Hope this helps!

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For exercises 4–9, find the value of x. round to the nearest tenth.[
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Kareem makes muffins using a ratio of 3.5 cups of flour for every 1.75 cups of sugar.
PtichkaEL [24]

Answer:

2 cups of flour

Step-by-step explanation:

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5 0
3 years ago
Kristen lives directly east of the park. The football field is directly south of the park. The library sits on the line formed b
klemol [59]

Imagine right triangle PHF, where P - park, H - home and F - football field, then PH, PF are legs and HF is hypotenuse . Denote point L to be library. You know that point L lies on the segment FH and FL=8, LH=2. Also you know that PL is an altitude to the hypotenuse.

Use the property of altitude drawn from the vertex of right angle to the hypotenuse (the length of the altitude is geometrical mean between legs' projections onto hypotenuse):

PL=\sqrt{HL\cdot LF},\\  PL=\sqrt{2\cdot 8}=\sqrt{16} =4 mi.

This means that the distance between park and libriry is 4 miles.

Consider right triangle PLF ( angle L is right angle and PF - hypotenuse). By the Pythagorean theorem,

PF^2=PL^2+LF^2,\\ PF^2=4^2+8^2,\\ PF^2=16+64=80,\\ PF=\sqrt{80} =4\sqrt{5} mi. The distance between park and football field is 4\sqrt{5} miles.

Answer: the distance between park and libriry is 4 miles and the distance between park and football field is 4\sqrt{5} miles.

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3 years ago
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