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vlada-n [284]
3 years ago
10

Erin gets her exercise by running. The graph shows the distances she covers in a given amount of time. How many hours does it ta

ke for Erin to run 25 miles?

Mathematics
2 answers:
ivanzaharov [21]3 years ago
7 0

Answer:

2½ h  

Step-by-step explanation:

Assume the graph is like the one below.

The graph shows how Erin's distance varies with time.

To find out how long it takes Erin to cover 25 mi, find 25 mi on the vertical axis.

From there, draw a horizontal line until it hits the graph.

Then drop a vertical line to the horizontal axis.

It hits half-way between 2 and 3.

It takes Erin 2½ h to run 25 mi.

ser-zykov [4K]3 years ago
7 0

Answer:

C because 25miles is in between 2and 3 hours

  • (2+3)/2=2.5
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Solve this inequality. 7.2-3w<4.5
zlopas [31]

Answer:

w>0.9

Step-by-step explanation:

7.2-3w<4.5

-7.2       -7.2

-3w<-2.7

/-3    /-3

w>0.9

The inequality switches when divided by a negative.

-hope it helps

8 0
2 years ago
Read 2 more answers
The outside temperature can be estimated based on how fast crickets chirp. At 104 chirps per minute, the temperature is 63 degre
Rasek [7]

Answer:

For 124 chirps per minute the temperature is 68 ºF.

For 68 chirps per minute the temperature is 54 ºF.

Step-by-step explanation:

Linear functions are those whose graph is a straight line. A linear function has the following form

f(x)=b+mx

b is the constant term or the y intercept. It is the value of the dependent variable when x = 0.

m is the coefficient of the independent variable. It is also known as the slope and gives the rate of change of the dependent variable.

We know that

  • At 104 chirps per minute, the temperature is 63 ºF.
  • At 176 chirps per minute, the temperature is 81 ºF.

This information can be converted to Cartesian coordinates (x, y). Where x = the number of chirps per minute and  y = the temperature in ºF.

To find a linear function that let us find the outside temperature from how fast crickets chirp we must:

  • Find the slope:

m=\frac{y_2-y_1}{x_2-x_1}=\frac{81-63}{176-104}=\frac{1}{4}

  • Find the equation:

81=\frac{1}{4}\cdot 104+b

Solving for b

b=81-\frac{1}{4} (176)=37

Therefore, the linear function is

y=\frac{1}{4} \cdot x+37

Now, using this linear function we can know the temperature when we know the chirps per minute:

For 124 chirps per minute the temperature is:

y=\frac{1}{4} \cdot (124)+37=68

For 68 chirps per minute the temperature is:

y=\frac{1}{4} \cdot (68)+37=54

6 0
2 years ago
3.
natima [27]

Answer:

See explanation

Step-by-step explanation:

Let x be the number of spade shovels, y -the number of flat shovels and z - the number of square showels sold that day.

The store keeps an inventory of 80 shovels, then

x+y+z=80

The store always buy twice as many spade shovels as square, so

x=2z

The total cost of all shovels is

16x+9.60y+12.80z=1,072

a) The system of three equations is

\left\{\begin{array}{l}x+y+z=80\\ \\x=2z\\ \\16x+9.60y+12.80z=1,072\end{array}\right.

b) In matrix form this is

\left(\begin{array}{ccc}1&1&1\\ 1&0&-2\\ 16&9.60&12.80\end{array}\right)\cdot \left(\begin{array}{c}x\\y\\z\end{array}\right)=\left(\begin{array}{c}80\\0\\1,072\end{array}\right)

c) The determinant is

\left\|\begin{array}{ccc}1&1&1\\ 1&0&-2\\ 16&9.60&12.80\end{array}\right\|=0-32+9.60-0+19.20-12.80=-16

d) Find three determinants:

\left\|\begin{array}{ccc}80&1&1\\ 0&0&-2\\ 1,072&9.60&12.80\end{array}\right\|=0-2,144+0-0+1,536-0=-608

\left\|\begin{array}{ccc}1&80&1\\ 1&0&-2\\ 16&1,072&12.80\end{array}\right\|=0-2,560+1,072-0+2,144-1,024=-368

\left\|\begin{array}{ccc}1&1&80\\ 1&0&0\\ 16&9.60&1,072\end{array}\right\|=0+0+768-0-0-1,072=-304

So,

x=\dfrac{-608}{-16}=38\\ \\y=\dfrac{-368}{-16}=23\\ \\z=\dfrac{-304}{-16}=19

e) If the store doubled all prices and inventory, then the new matrix is

\left(\begin{array}{ccc}1&1&1\\ 1&0&-2\\ 32&19.20&25.60\end{array}\right)\cdot \left(\begin{array}{c}x\\y\\z\end{array}\right)=\left(\begin{array}{c}160\\0\\2,144\end{array}\right)

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