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3 years ago

What is the distance between (-2 1/2, -3) and (1, -3)

Mathematics

2 answers:

Igoryamba3 years ago

4 0

Answer:

Step-by-step explanation:

(-2 1/2, -3) = (-5/2 , -3) & (1, -3)

$Distance=\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}\\\\ =\sqrt{(1-[\frac{-5}{2}])^{2}+(-3-[-3])^{2}}\\\\ =\sqrt{(1+\frac{5}{2})^{2}+(-3+3)^{2}}\\\\ =\sqrt{(\frac{7}{2})^{2}} \\\\=\frac{7}{2}\\\\=3\frac{1}{2}$

Bingel [31]3 years ago

3 0

Answer:

D) 3 1/2

Step-by-step explanation:

d = √(x₂ - x₁)² + (y₂ - y₁)²

x₂ = 1

x₁ = - 2 1/2 = - 5/2

y₂ = - 3

y₁ = - 3

d = √( 1 + 5/2)² + (- 3 + 3)²

= √(2/2 + 5/2) + 0

= √(7/2)²

= 7/2

= 3 1/2

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