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3 years ago

What is the sum of the measures of the interior angles of a pentagon and 10-gon (decagon)?

Mathematics

2 answers:

Arada [10]3 years ago

5 0

Answer:

540

Step-by-step explanation:

sum of interior angles =(n-4)90

(10-4)90=

6×90=540

oksano4ka [1.4K]3 years ago

3 0

Answer: the sum of the measures of the interior angles of a pentagon is 540 degrees and that of a decagon is 1440 degrees

Step-by-step explanation:

The formula for finding the sum of the measure of the interior angles in a regular polygon is expressed as (n - 2) × 180.

A Pentagon has 5 sides. This means that the sum of the angles in a heptagon is

180(5 - 2) = 180 × 3 = 540 degrees

A Decagon has 10 sides. This means that the sum of the angles in a heptagon is

180(10 - 2) = 180 × 8 = 1440 degrees

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