Answer:
e. The probability of observing a sample mean of 5.11 or less, or of 5.29 or more, is 0.018 if the true mean is 5.2.
Step-by-step explanation:
We have a two-tailed one sample t-test.
The null hypothesis claims that the pH is not significantly different from 5.2.
The alternative hypothesis is that the mean pH is significantly different from 5.2.
The sample mean pH is 5.11, with a sample size of n=50.
The P-value of the test is 0.018.
This P-value corresponds to the probability of observing a sample mean of 5.11 or less, given that the population is defined by the null hypothesis (mean=5.2).
As this test is two-tailed, it also includes the probability of the other tail. That is the probability of observing a sample with mean 5.29 or more (0.09 or more from the population mean).
Then, we can say that, if the true mean is 5.2, there is a probability P=0.018 of observing a sample of size n=50 with a sample mean with a difference bigger than 0.09 from the population mean of the null hypothesis (5.11 or less or 5.29 or more).
The right answer is e.
Answer:
2 sqrt(19)
Step-by-step explanation:
We know that the angle between the two hands
360 /12 *2 = 60 degrees
We divide by 12 because there are 12 number and multiply by 2 because there are 2 number between 10 and 12
This is a triangle where we know 2 sides and the angle between them.
We can use the law of cosines to determine the third side
c^2 = a^2 + b^2 -2abcosC
Where C is the angle between sides a and b
a =4 and b = 10 C = 60 and we are looking for side c
c^2 = 4^2 + 10^2 -2*4*10 cos60
c^2 =16+100 - 80cos 60
c^2 = 76
Take the square root of each side
sqrt(c^2) = sqrt(76)
c = sqrt(76)
c =sqrt(4) sqrt(19)
c =2 sqrt(19)
Initial velocity (u) = 0m/s
Final velocity (v) = 20m/s
Time (t) = 10 s
Acceleration (a)
= (v - u)/t
= [(20m/s) - (0m/s)]/10s
= (20m/s)/10s
= (20m/s²)/10
=> 2m/s²
1. -48v-5/45 2.44-r/2 3. x=2
Answer:
Its 40 degrees
Step-by-step explanation:
60+80=140
180-140=40 (a straight line is always 180 degrees)
Hope it helped
