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Katena32 [7]
4 years ago
11

Jane has a 5x7 inch photograph that she wants enlarged to a 10x14 inch

Mathematics
2 answers:
il63 [147K]4 years ago
7 0
The scale factor is 2 so you would increase each length by 2
dlinn [17]4 years ago
6 0
Im not sure if this will help

5*7 ----->  5/7
10*14 ------> 10/14

do 5 * 2 =10
do 7* 2 = 14

You have to multiply it by 2 to get the 10*14 inch
Hope this helps :D
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help finding the perimter of 78.4 inches whats the length of each side and show me how to work the promblem
LuckyWell [14K]
A square has four even sides and the perimeter is equal to the sum of all of the sides.
P=s+s+s+s=4s
So we can evaluate the equation for P and then solve for s.
78.4=4s \\  \frac{78.4}{4} =s \\ s=19.6in
6 0
3 years ago
What are the leading coefficient and degree of the polynomial? <br> 20-w^9+2w^3+12w
Ilya [14]

I assume you want the leading coefficient because there is only 1.


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The degree of this function is 9. It is a ninth degree polynomial function. Why 9? It is a 9th degree polynomial because 9 is the greatest power.


6 0
4 years ago
77+ 2(3x – 5) = 8 – 3(2x + 1)<br> 78 2 + 3(2 -7) – 0 - 13 I 1).
nika2105 [10]

Answer:

-31/6

Step-by-step explanation:

77+2(3x-5)=8-3(2x+1)

77+6x-10=8-6x-3

77-10+6x=8-3-6x

67+6x=5-6x

67+6x-(-6x)=5

67+6x+6x=5

67+12x=5

12x=5-67

12x=-62

x=-62/12

simplify

x=-31/6

3 0
3 years ago
In a 45-45-90 right triangle, what is the ratio of the length of one leg to the
8_murik_8 [283]
In a 45-45-90 triangle, both of the legs have the same length and the ratio of one leg to the hypotenuse is 1:sqrt(2).
7 0
3 years ago
Can anyone help me in this whole math question? Especially Number b and c. <br>Thanks. ​
Bogdan [553]

Answer:

Irregular polygons are polygons that do not have equal sides or equal angles. When finding the area of an irregular polygon, partition the polygon into smaller regular polygon shapes. You can then plug those measurements into their respective area formulas and multiply to find the area of one part of the shape.

This is 16cm.

5 0
3 years ago
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