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3 years ago

What is the LCM for (x + 3)2(x – 2) and (x + 3)(x2 – 16)?

Mathematics

1 answer:

Shkiper50 [21]3 years ago

8 0

Answer:

(x+3)^2(x-2)(x^2-16)

Step-by-step explanation:

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Solve the system by substitution.<br> y = -6x<br> - 2x - y = 16

vivado [14]

Answer:

X=4 and Y= -24

Step-by-step explanation:

Step 1: −6x for y in−2x−y=16:

−2x−y=16

−2x−−6x=16

4x=16

4x/4=16/4

x=4

----------------------------------------------------------------------

y=−6x

y=(−6)(4)

y=−24

y=-24

3 0

3 years ago

What’s the product of 1.5% of 67,200

Blizzard [7]

Answer:

1008

Step-by-step explanation:

Its easy, just multiply 67,200 by 1.5%, or 1.5*0.01 which is 0.015. 62700 * 0.015 equals 1008

5 0

3 years ago

Write an equation of a parabola with the given vertex and focus.<br> vertex (-1,3); focus (-1,4)

NeX [460]

See https://web2.0calc.com/questions/i-need-help_4982.

6 0

3 years ago

the dilation from LMN to triangle L’M’N’ has a scale factor of 1/3 , write the coordinates for L’M’N’ and then graph both the pr

mina [271]

Answer:

Hi... U should do like this..

8 0

3 years ago

A ballplayer catches a ball 3.4s after throwing it vertically upward. with what speed did he throw it, and what height did it re

Daniel [21]

From the equation of motion, we know,

$s=ut+\frac{1}{2}at^{2}$

Where s= displacement

u= initial velocity

a= gravitational force

t= time

Displacement is 0 since the ball comes back to the same point from where it was thrown.

A = $-9.8m/s^{2}$ since the ball is thrown upwards.

Plug the known values into the equation.

=> $0=u\left ( 3.4 \right )+\frac{1}{2}\left ( -9.81 \right )(3.4^{2})$

Solving for u gives :

u= 16.67 m/ sec ....... equation (1)

At maximum height, final velocity i.e v is 0

Time take to reach the top = $\frac{3.4}{2} = 1.7 sec$

$v^{2}=u^{2}+2as$

=> $0=(16.67)^{2}+2(-9.81)(s)$

Solving for s we get

s= 14.16 m

4 0

3 years ago