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iren2701 [21]
3 years ago
12

Please solve this question.

Mathematics
1 answer:
andre [41]3 years ago
8 0
  • <em>Answer:</em>

<em>x = - 2</em>

<em>y = 5</em>

  • <em>Step-by-step explanation:</em>

<em>Hi there ! </em>

<em>2x + 9 = y</em>

<em>y = - 4x - 3</em>

<em> </em>

<em>equality</em>

<em>2x + 9 = - 4x - 3</em>

<em>2x + 4x = - 9 - 3</em>

<em>6x = - 12</em>

<em>x = - 12 : 6</em>

<em>x = - 2</em>

<em>replace x = - 2</em>

<em>2(-2) + 9 = y</em>

<em>- 4 + 9 = y</em>

<em>y = 5</em>

<em>Good luck !</em>

<em />

<em />

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8{(5*3)+(2*5)+(2*10)=
DerKrebs [107]

Answer:

8(5*3)+(2*5)+(2*10)=360

Step-by-step explanation:

8(15)+(10)+(20)=

8(45)=

6 0
3 years ago
Read 2 more answers
A system contains n atoms, each of which can only have zero or one quanta of energy. How many ways can you arrange r quanta of e
My name is Ann [436]

Answer:

\mathbf{a)} 2\\ \\ \mathbf{b)} 184 \; 756 \\ \\\mathbf{c)}  \dfrac{(2\times 10^{23})!}{(10^{23}!)(10^{23})!}

Step-by-step explanation:

If the system contains n atoms, we can arrange r quanta of energy in

                         \binom{n}{r} = \dfrac{n!}{r!(n-r)!}

ways.

\mathbf{a)}

In this case,

                                n  = 2, r=1.

Therefore,

                    \binom{n}{r} = \binom{2}{1} = \dfrac{2!}{1!(2-1)!} = \frac{2 \cdot 1}{1 \cdot 1} = 2

which means that we can arrange 1 quanta of energy in 2 ways.

\mathbf{b)}

In this case,

                                n  = 20, r=10.

Therefore,

                    \binom{n}{r} = \binom{20}{10} = \dfrac{20!}{10!(20-10)!} = \frac{10! \cdot 11 \cdot 12 \cdot \ldots \cdot 20}{10!10!} = \frac{11 \cdot 12 \cdot \ldots \cdot 20}{10 \cdot 9 \cdot \ldots \cdot 1} = 184 \; 756

which means that we can arrange 10 quanta of energy in 184 756 ways.

\mathbf{c)}

In this case,

                                n = 2 \times 10^{23}, r = 10^{23}.

Therefore, we obtain that the number of ways is

                    \binom{n}{r} = \binom{2\times 10^{23}}{10^{23}} = \dfrac{(2\times 10^{23})!}{(10^{23})!(2\times 10^{23} - 10^{23})!} = \dfrac{(2\times 10^{23})!}{(10^{23}!)(10^{23})!}

3 0
3 years ago
The quotient of a number and 5 is less than 4
cupoosta [38]

Answer:

n ÷ 5 < 4

Step-by-step explanation:

Quotient is to divide.

Let n be the unknown number.

Now you have the equation needed.

8 0
3 years ago
More help is appreciated:))
Lera25 [3.4K]

Step-by-step explanation:

You need to translate all the points to the right 3 and up 6

Therefore, you are going to use this formula:

(x,y) ⇾ (x + 3, y + 6)

This is the same format as the previous problem, if you have noticed.

Using this, plug in each coordinate, starting with  P (5, -1)

(5, -1) ⇾ ( 5 + 3, -1 + 6)

(5, -1) ⇾ ( 8, 5 )

P^{1} = (8, 5)

Now point Q, (0, 8)

(0, 8) ⇾ (0 + 3, 8 + 6)

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Q^{1} = (3, 14)

And last but not least, the point R, (7, 5)

(7, 5) ⇾ (7 + 3, 5 + 6)

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R^{1} = (10, 11)

Therefore, P^{1} = (8, 5), Q^{1} = (3, 14), R^{1} = (10, 11) is your answer. This is the 4th option or D.

Hope this for you to understand this a bit more! =D

6 0
3 years ago
Mrs.Anderson is giving a test in her third period class she has decided to record the amount of time that each student takes to
ICE Princess25 [194]

The graph Plot of the given results shown represents; A relation only

<h3>How to interpret a scatter plot?</h3>

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Thus, the graph plot can only be a relation as it is not a function as seen from the points plotted in the graph.

The complete question is;

Mrs. Anderton is giving a test in her third-period class. She has decided to record the amount of time that each student takes to finish the test (in minutes) and compare that to the grade each student receives on the test (out of 100). A plot of her results is below. Which of the following does this situation represent?

A. both a relation and a function

B. a function only

C. neither a relation nor a function

D. a relation only

Read more about Scatter Plot at; brainly.com/question/6592115

#SPJ1

8 0
2 years ago
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