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4 years ago

5

There are 24 members on a swim team. How many different combinations of 5 swimmers can be chosen to sit in the front row for a t

eam photo?

2 answers:

Charra [1.4K]4 years ago

7 0

Answer: 42504

Step-by-step explanation:

We know that the combination of n things taken x at a time is given by :-

$^nC_x=\dfrac{n!}{x!(n-x)!}$

Given : There are 24 members on a swim team.

i.e. n= 24

Then, the number of different combinations of 5 swimmers can be chosen to sit in the front row for a team photo :-

$^{24}C_5=\dfrac{24!}{5!(24-5)!}=\dfrac{24!}{5!19!}=42504$

Therefore, the number of different combinations of 5 swimmers can be chosen to sit in the front row for a team photo = 42504

mart [117]4 years ago

3 0

This is a question combinations.

Number of combination to choose 5 swimmers from 24 members = 24C5 = 24!/[5!*(25-5)!] = 42504

Therefore, there are 42504 ways in which 5 swimmers can be chosen to sit on the front row from 24 members swim team.

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The permitted of a rectangle is 24 inches.The length is 2 inches.Use the numbers below to complete an equation to solve for the

german

Answer:

$24=2(2)+2w$

$w=10$

Step-by-step explanation:

We have been given that the perimeter of a rectangle is 24 inches. The length is 2 inches. We are supposed to write an equation to solve for the width.

We know that the perimeter of the rectangle is 2 times the sum of its width and length.

$P=2l+2w$

Upon substituting our given values in perimeter equation, we will get:

$24=2(2)+2w$

Let us solve for width.

$24=4+2w$

$24-4=4-4+2w$

$20=2w$

$\frac{20}{2}=\frac{2w}{2}$

$10=w$

Therefore, the width of the rectangle would be 10 inches.

4 0

4 years ago

BRAINLIEST! URGENT! If you can answer this, please help. If you can explain how you got that answer, I will mark you Brainliest.

Karo-lina-s [1.5K]

Answer:

$\mathrm{A.\:}x+2y=a$

Step-by-step explanation:

In standard form $ax+by=c$ , any point the line passes through will make the inequality true. We can simply use any point given to find the equation of the line:

We can write the following system of equations from two points from the table:

$\begin{cases}d\cdot3a+e\cdot(-a)=f\cdot a\\d\cdot5a+e\cdot(-2a)=f\cdot a\end{cases}$

Solving, we get:

For $a \notin 0$ ,

$d=1,\\e=2,\\f=1$

Therefore, our equation is:

$dx+ey=fa,\\1x+2y=1a,\\\fbox{$x+2y=a$}$ .

8 0

3 years ago

Help please Math problems?

Andrews [41]

The answer is ep I think

3 0

4 years ago

Read 2 more answers

When completing the square on the equation c2 + 110 = 12, the resulting solution is:<br> It

Delvig [45]

Answer:

$c=1$ and $c=-12$

Step-by-step explanation:

The correct equation is:

$c^2+11c=12$

To solve by completing the square method.

Solution:

We have:

$c^2+11c=12$

In order to solve by completing the square method we will carry out the following operations to the given equation to get a perfect square binomial.

We can write as:

$c^2+2.\frac{11}{2}c=12$

$c^2+2.\frac{11}{2}c+(\frac{11}{2})^2-(\frac{11}{2})^2=12$

$(c+\frac{11}{2})^2-(\frac{11}{2})^2=12$ [As $c^2+2.\frac{11}{2}c+(\frac{11}{2})^2=(c+\frac{11}{2})^2$ ]

Adding both sides by $(\frac{11}{2})^2$

$(c+\frac{11}{2})^2-(\frac{11}{2})^2+(\frac{11}{2})^2=12+(\frac{11}{2})^2$

$(c+\frac{11}{2})^2=12+\frac{121}{4}$

Taking LCD to add fraction.

$(c+\frac{11}{2})^2=\frac{48}{4}+\frac{121}{4}$

$(c+\frac{11}{2})^2=\frac{169}{4}$

Taking square root both sides.

$\sqrt{(c+\frac{11}{2})^2}=\sqrt{\frac{169}{4}}$

$c+\frac{11}{2}=\pm\frac{13}{2}$

Subtracting both sides by $\frac{11}{2}$ :

$c+\frac{11}{2}-\frac{11}{2}=\pm\frac{13}{2}-\frac{11}{2}$

$c=\pm\frac{13}{2}-\frac{11}{2}$

So, we have:

$c=\frac{13}{2}-\frac{11}{2}$ and $c=-\frac{13}{2}-\frac{11}{2}$

$c=\frac{2}{2}$ and $c=\frac{-24}{2}$

$c=1$ and $c=-12$ (Answer)

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4 years ago

The probability of Derek getting a hit when he comes to bat is 30%. How many hits should he expect to get if he comes to bat 450

AVprozaik [17]

450 divided by 30 =90

90 times

5 0

3 years ago