Answer:
(x-2)^2 + (y - 5)^2 = 16
Step-by-step explanation:
Given the standard form of an equation of a circle
(x-h)^2+(y-k)^2=r^2
If (h, k) = (5,2) and r = 4
Substitute
(x-2)^2 + (y - 5)^2 = 4^2
(x-2)^2 + (y - 5)^2 = 16
Hence the required equation is (x-2)^2 + (y - 5)^2 = 16
Add common -2x+-5x=-7x+8
-7x+8
Answer:
x=2.080084
Step-by-step explanation: take cube root
The square of a positive integer added to 4 times the integer is 437..
x2 + 4x = 437
I chose to do this by completing the square..
x2+4x+4 = 437 + 4
(x+2)2 = 441
Take square root of both sides
x+2 = ±√441
x = -2 ± 21
x = -23 or x = 19
x = 19
Answer:
The answer is 10 I believe! A whole triangle is equal to 180 degrees so 180-70-60-60= -10. So we have to add 10 to equal it to zero. Hope this helped
Step-by-step explanation:
