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VashaNatasha [74]
3 years ago
7

907 rounded to the nearest ten is ?

Mathematics
2 answers:
aniked [119]3 years ago
4 0

Answer:910

Step-by-step explanation: it rounds up because if the last number is more than 5 you round up

coldgirl [10]3 years ago
3 0
If you mean tenth, it is 907 because there is no decimal point. if you mean ten, i would assume it would be 910.
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iogann1982 [59]

If

y=\displaystyle\sum_{n=0}^\infty a_nx^n

then

y'=\displaystyle\sum_{n=1}^\infty na_nx^{n-1}=\sum_{n=0}^\infty(n+1)a_{n+1}x^n

The ODE in terms of these series is

\displaystyle\sum_{n=0}^\infty(n+1)a_{n+1}x^n+2\sum_{n=0}^\infty a_nx^n=0

\displaystyle\sum_{n=0}^\infty\bigg(a_{n+1}+2a_n\bigg)x^n=0

\implies\begin{cases}a_0=y(0)\\(n+1)a_{n+1}=-2a_n&\text{for }n\ge0\end{cases}

We can solve the recurrence exactly by substitution:

a_{n+1}=-\dfrac2{n+1}a_n=\dfrac{2^2}{(n+1)n}a_{n-1}=-\dfrac{2^3}{(n+1)n(n-1)}a_{n-2}=\cdots=\dfrac{(-2)^{n+1}}{(n+1)!}a_0

\implies a_n=\dfrac{(-2)^n}{n!}a_0

So the ODE has solution

y(x)=\displaystyle a_0\sum_{n=0}^\infty\frac{(-2x)^n}{n!}

which you may recognize as the power series of the exponential function. Then

\boxed{y(x)=a_0e^{-2x}}

7 0
3 years ago
HELP PLSSSSSSSSSSSSSSS ASAP
makvit [3.9K]

Answer:

26

Step-by-step explanation:

Sydney = x

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Hope that helps!

6 0
2 years ago
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What set of reflections would carry hexagon ABCDEF onto itself?
Marianna [84]

When a set of reflections that carry a shape onto itself, it means that the final position of the shape will be the same as its original location

Reflections <em>(a) y=x, x-axis, y=x, y-axis </em>would carry the hexagon onto itself

First; we test the given options, until we get the true option

<u>(a) y=x, x-axis, y=x, y-axis</u>

The rule of reflection y =x is:

(x,y) \to (y,x)

The rule of reflection across the x-axis is:

(x,y) \to (x,-y)

So, we have:

(y,x) \to (y,-x)

The rule of reflection y =x is:

(x,y) \to (y,x)

So, we have:

(y,-x) \to (-x,y)

Lastly, the reflection across the y-axis is:

(x,y) \to (-x,y)

So, we have:

(-x,y) \to (x,y)

So, the overall transformation is:

(x,y) \to (x,y)

Notice that, the original and final coordinates are the same.

This means that:

Reflections <em>(a) y=x, x-axis, y=x, y-axis </em>would carry the hexagon onto itself

Read more about reflections at:

brainly.com/question/938117

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2 years ago
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Answer:

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Then plug it back in to the equations.

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3 years ago
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The answer is $312500

3 0
3 years ago
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