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ElenaW [278]
2 years ago
11

What is the first step to solve the equation x^2-3=15​

Mathematics
2 answers:
Otrada [13]2 years ago
6 0

You will need to add 3 to each side.

x^2-3=15

    +3   +3

x^2=12

and go from there

Vanyuwa [196]2 years ago
5 0

Answer:

<h2>C. Add 3 to both sides of the equation.</h2>

Step-by-step explanation:

x^2-3=15\qquad\text{add 3 to both sides of the equation}\\\\x^2-3+3=15+3\\\\x^2=15\to x=\pm\sqrt{15}

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In △ABC, point D∈ AB with AD:DB=5:3, point E∈ BC so that BE:EC=1:4. If AABC=40 in2, find AADC, ABDC, and ACDE.
DIA [1.3K]

Answer: Using the proportions between the segments, the area of the triangles are:

1. Area of triangle ADC is 25 in^2.

2. Area of triangle BDC is 15 in^2.

3. Area of triangle CDE is 12 in^2.


Please, see the attached files.

Thanks.

8 0
3 years ago
The sum of two numbers, x and y, is 12. The difference of x and two times y is 6. What are the values of x and y?
Aleksandr-060686 [28]
The answer is: x = 10, y = 2

Leave a thanks because your welcome :)

Work:

x + y = 12
(10) + (2)+  = 12
Correct

x - 2y = 6
(10) - 2(2) = 6
10 - 4 = 6
Correct
8 0
3 years ago
13+(14+x)=. please answer
Mumz [18]
27+x simplify the expression
5 0
3 years ago
Does AN times E equal to ABN If A= 1, B= 5 , and N= 0
adelina 88 [10]

Answer:

no it would equal ANE

Step-by-step explanation:

7 0
2 years ago
Mr. Jones purchased two sodas.
kondaur [170]

Answer:

  the prices were $0.05 and $1.05

Step-by-step explanation:

Let 'a' and 'b' represent the costs of the two sodas. The given relations are ...

  a + b = 1.10 . . . . the total cost of the sodas was $1.10

  a - b = 1.00 . . . . one soda costs $1.00 more than the other one

__

Adding these two equations, we get ...

  2a = 2.10

  a = 1.05 . . . . . divide by 2

  1.05 -b = 1.00 . . . . . substitute for a in the second equation

  1.05 -1.00 = b = 0.05 . . . add b-1 to both sides

The prices of the two sodas were $0.05 and $1.05.

_____

<em>Additional comment</em>

This is a "sum and difference" problem, in which you are given the sum and the difference of two values. As we have seen here, <em>the larger value is half the sum of the sum and difference</em>: a = (1+1.10)/2 = 1.05. If we were to subtract one equation from the other, we would find <em>the smaller value is half the difference of the sum and difference</em>: b = (1.05 -1.00)/2 = 0.05.

This result is the general solution to sum and difference problems.

5 0
2 years ago
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