Answer:
20
Step-by-step explanation:
Plug in -4 for n:
(-4)^2 - (-4) = 16 + 4 = 20
I believe that none would be irrational; an irrational number can't have terminating or repeating decimals. 3/8= .375, (56/8)^4=7^4=2,401, 36^4/4^4=6561, and .19 repeating is a repeating decimal.
First of all, we need all logarithms to have the same base. So, we use the formula

To change the second term as follows:

Finally, using the property

we have

So, the equation becomes

We can now use the formula

to write the equation as

Now consider both sides as exponents of 2:

This equation has no "nice" solution, so I guess the problem is as simplifies as it can be
Answer:
Denote adding term = a
a = (5/6x) - 4 - (1/2x) - 4
a = (5/6x) - (1/2x)
a = (5/6x) - (3/6x)
a = (2/6x)
a = (1/3x)
*******************************
a = (5/6)x - 4 - (1/2)x - 4
a = (5/6)x - (1/2)x
a = (5/6 - 1/2)x
a = (1/3)x
Hope this helps!