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yKpoI14uk [10]
2 years ago
13

When solving the equation, which is the best first step to begin to simplify the equation?

Mathematics
2 answers:
boyakko [2]2 years ago
6 0

Answer:

<h3>Negative one-half (negative 2) (x + 3) = negative 10 (negative one-half)</h3>

Step-by-step explanation:

Given the expression

- 2 (x + 3) = - 10

The first step in solving the expression is to multiply both sides by -1/2 as shown;

-1/2(-2)(x+3) = -1/2(-10)

(x +3) = 1/2(10)

x + 3 = 5

x = 5-3

x = 2

Hence the correct option is Negative one-half (negative 2) (x + 3) = negative 10 (negative one-half)

musickatia [10]2 years ago
3 0

Answer:

Negative one-half (negative 2) (x + 3) = negative 10 (negative one-half)

Step-by-step explanation:

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HELP PLEASEEEE!!!
Anna35 [415]
B. I mean it’s super easy but I hope it helps
3 0
2 years ago
Please help<br><br><br> AOB = ?<br><br> BOC = ?<br><br> BOD = ?
goldfiish [28.3K]
From the diagram, we know that it is an angle that adds up to 360

So

x+4x+2x+10+5x+50=360


Gather like terms

12x+60=360

Move sixty to the other side as a negative number

12x=300

Divide both sirs by twelve

x is equal to 25

AOB is 2x+10

Sub x in 2*25+10

AOB is 60

BOC is 5x+50

5*25+50, which is 175

BOD is x+2x+10

Which is 3x+10

Sub x

3*25+10 which is 85

:)
7 0
3 years ago
Read 2 more answers
Plz solve this question <br>Its urgent.....​
Maksim231197 [3]

Answer:

Step-by-step explanation:

tan Θ + tan 2Θ + √3 tan Θ tan 2Θ = √3

tan Θ + tan 2Θ = √3 - √3 tan Θ tan 2Θ

tan Θ + tan 2Θ = √3 ( 1 - tan Θ tan 2Θ)

(tan Θ + tan 2Θ) / (1 - tanΘ tan 2Θ) = √3

tan(Θ  + 2Θ) = √3

tan 3Θ = tan (\frac{\pi }{3})           we know tan Θ = tan α; Θ = nΠ + α, n belongs to z

3Θ = nΠ + Π/3

Θ = nπ/3 + Π/9 for all n in Z

4 0
3 years ago
This question has three parts. Answer the parts in order.
nalin [4]

Answer:

The area of the smallest section is A_{1}=100yd^{2}

The area of the largest section is A_{2}=625yd^{2}

The area of the remaining section is A_{3}=250yd^{2}

Step-by-step explanation:

Please see the picture below.

1. First we are going to name the side of the larger square as x.

As the third section shares a side with the larger square and the four sides of a square are equal, we have the following:

- Area of the first section:

A_{1}=10yd*10yd

A_{1}=100yd^{2}

- Area of the second section:

A_{2}=x^{2} (Eq.1)

- Area of the third section:

A_{3}=width*length

A_{3}=10yd*x (Eq.2)

2. The problem says that the total area of the enclosed field is 975 square yards, and looking at the picture below, we have:

A_{1}+A_{2}+A_{3}=975yd^{2}

Replacing values:

100+x^{2}+10x=975

Solving for x:

x^{2}+10x-875=0

x=\frac{-10+\sqrt{100+(4*875)}}{2}

x=\frac{-10+\sqrt{3600}}{2}

x=\frac{-10+60}{2}

x=25

3. Replacing the value of x in Eq.1 and Eq.2:

- From Eq.1:

A_{2}=25^{2}

A_{2}=625yd^{2}

- From Eq.2:

A_{3}=10*25

A_{3}=250yd^{2}

3 0
2 years ago
Pl help it’s for a grade
True [87]
I think the answer is b
I hope this helps :)
5 0
3 years ago
Read 2 more answers
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