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Phantasy [73]
3 years ago
8

Lola measures three buttons for a shirt she is making. One button is 1/8 inch, one is 3/8 inch, and one is 1/4 inch. Which butto

n is smallest? Which is largest?
Mathematics
1 answer:
Basile [38]3 years ago
5 0
Given that the size of the buttons are:
1/8 inch, 3/8 inch and 1/4 inch
To compare the lengths we first convert the fractions into decimals for easy comparison.
To convert fractions into decimals we divide the numerator by the denominator:
1/8=0.125
3/8=0.375
1/3=0.25
from the above decimals we can see that 0.125 is the smallest and hence we conclude that the smallest button is 1/8 inches. The largest button is 3/8 inches. 
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Gwar [14]

You can use any calculator in Maths.

7 0
3 years ago
Question 2 Please
NeX [460]

Answer:

Step-by-step explanation:

Start by moving the 3 to the other side of the equals sign to get

tan^2(2\theta)=3

tan^2(2\theta)=(tan(2\theta))(tan(2\theta)) so with that replacement:

(tan(2\theta))(tan(2\theta))=3

By the Zero Product Property,

tan(2\theta)=3 or tan(2\theta)=3

Yes these are both the same, so we only need one of them.  Once we find the angle, they are both the same, so we only need one of these equations.

If

tan(2\theta)=3, take the inverse tangent of both sides to give you:

2\theta=tan^{-1}(3) and

2\theta=71.565 so

\theta=35.8

Tangent increases in increments of pi or 180, so the other angle within the given interval is 35.8 + 180 = 215.8

6 0
3 years ago
Fugture out the question
levacccp [35]

Answer: Its right.

Step-by-step explanation:

5 0
3 years ago
-12-2x<-3x+2<-2(x-7)
Dafna11 [192]

x < 14 \\ x >  - 12
6 0
3 years ago
Read 2 more answers
A girl studied for 5 2/3 hours daily. She devotes 2 4/2 hours of her time for science and mathematics. How much time does she de
enot [183]

Given :

Number of hours studied daily , T=5\dfrac{2}{3} .

Time given for science and mathematics is , t=2\dfrac{4}{2} .

To Find :

How much time does she devote for other subjects .

Solution :

Let , time devote for other student is x .

So , Time left for other subject = Total time - Time taken by science and mathematics .

x=T-t\\\\x=5\dfrac{2}{3}-2\dfrac{4}{2}\\\\x=\dfrac{(5\times 3)+2}{3}- \dfrac{(2\times 2 )+4}{2}\\\\x=\dfrac{17}{3}-4\\\\x=\dfrac{17-(4\times 3)}{3}\\\\x=\dfrac{5}{3}=1\dfrac{2}{3}

Therefore , time devote for other subject is 1\dfrac{2}{3} hours .

Hence , this is the required solution .

8 0
4 years ago
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