Answer:
Step-by-step explanation:
For this exercise you need to find the Least Common Multiple (LCM).
The steps two find the Least Common Multiple are shown below:
1. Descompose the numbers into their prime factors.
2. Multiply the commons an non commons with the highest exponent. The product obtained will be the Least Common Multiple.
Knowing this, you can find the Least Common Multiple between 7 and 11. This is:
Therefore the smallest number of biscuits each must have baked is:
Answer:
-2/3
Step-by-step explanation:
Answer:
2) c) (x-3)² + (y+2)² = 25
5) x^2 +y^2 -8x -16y +54 = 0
6) x^2 +y^2 -10x -12y +36 = 0
Step-by-step explanation:
2) The standard form equation for a circle is ...
(x -h)^2 +(y -k)^2 = r^2
You are given the center: (h, k) = (3, -2) and a point on the circle. So, the equation will be ...
(x -3)^2 +(y +2)^2 = r^2
Since we know a point on the circle we know that ...
(7 -3)^2 +(1 +2)^2 = r^2 = 16 +9 = 25
So, the circle's equation is ...
(x -3)^2 +(y +2)^2 = 25 . . . . . matches choice C
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5) As in the previous problem, the standard form equation is ...
(x -4)^2 +(y -8)^2 = (-1-4)^2 +(7-8)^2 = 25+1 = 26
To put this in general form, we need to subtract 26 and eliminate parentheses.
x^2 -8x +16 +y^2 -16y +64 -26 = 0
x^2 +y^2 -8x -16y +54 = 0
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6) A circle tangent to the y-axis will have a radius equal to the x-value of the center point.
(x -5)^2 +(y -6)^2 = 5^2
x^2 -10x +25 +y^2 -12y +36 = 25
x^2 +y^2 -10x -12y +36 = 0
