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Vinil7 [7]
3 years ago
9

State all possible names for this figure

Mathematics
1 answer:
Len [333]3 years ago
8 0

Answer:

A quadrilateral and parallelogram

Step-by-step explanation:

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Raise g to the 7th power, multiply the result by 4, then subtract f from what you have
WINSTONCH [101]

Answer:

f - 4(g^7)

It's simple algebraic operations!

7 0
2 years ago
The glee club has a set of 48 classical cds and a set of 42 show tune cds. each set can be divided equally among the club member
Hoochie [10]
We have to find the GCF (Greatest Common Factor) of 48 and 42 here... 

Factors of 48:
1,2,3,4,6,8,12,16,24,48

Factors of 42: 
1,2,3,6,7,14,21,42

The largest common factor of these two numbers is 6. 


So, there can be a maximum of 6 members in the club.. 

Hope this helped!
6 0
3 years ago
Read 2 more answers
X + 7y = -4 <br> solve for x
GuDViN [60]
To solve for x
x+7y=-4
x=-4-7y
4 0
3 years ago
Read 2 more answers
Could the inverse of a non-function be a function? Explain or give an example.
Kitty [74]

Answer:

The inverse of a non-function mapping is not necessarily a function.

For example, the inverse of the non-function mapping \lbrace (0,\, 0),\, (0,\, 1),\, (1,\, 0),\, (1,\, 1) \rbrace\! is the same as itself (and thus isn't a function, either.)

Step-by-step explanation:

A mapping is a set of pairs of the form (a,\, b). The first entry of each pair is the value of the input. The second entry of the pair would be the value of the output.  

A mapping is a function if and only if for each possible input value x, at most one of the distinct pairs includes x\! as the value of first entry.

For example, the mapping \lbrace (0,\, 0),\, (1,\, 0) \rbrace is a function. However, the mapping \lbrace (0,\, 0),\, (1,\, 0),\, (1,\, 1) \rbrace isn't a function since more than one of the distinct pairs in this mapping include 1 as the value of the first entry.

The inverse of a mapping is obtained by interchanging the two entries of each of the pairs. For example, the inverse of the mapping \lbrace (a_{1},\, b_{1}),\, (a_{2},\, b_{2})\rbrace is the mapping \lbrace (b_{1},\, a_{1}),\, (b_{2},\, a_{2})\rbrace.

Consider mapping \lbrace (0,\, 0),\, (0,\, 1),\, (1,\, 0),\, (1,\, 1) \rbrace\!. This mapping isn't a function since the input value 0 is the first entry of more than one of the pairs.

Invert \lbrace (0,\, 0),\, (0,\, 1),\, (1,\, 0),\, (1,\, 1) \rbrace\! as follows:

  • (0,\, 0) becomes (0,\, 0).
  • (0,\, 1) becomes (1,\, 0).
  • (1,\, 0) becomes (0,\, 1).
  • (1,\, 1) becomes (1,\, 1).

In other words, the inverse of the mapping \lbrace (0,\, 0),\, (0,\, 1),\, (1,\, 0),\, (1,\, 1) \rbrace\! would be \lbrace (0,\, 0),\, (1,\, 0),\, (0,\, 1),\, (1,\, 1) \rbrace\!, which is the same as the original mapping. (Mappings are sets. There is no order between entries within a mapping.)

Thus, \lbrace (0,\, 0),\, (0,\, 1),\, (1,\, 0),\, (1,\, 1) \rbrace\! is an example of a non-function mapping that is still not a function.

More generally, the inverse of non-trivial ellipses (a class of continuous non-function \mathbb{R} \to \mathbb{R} mappings, including circles) are also non-function mappings.

3 0
2 years ago
What is the remainder when 2x^3−9x^2+11 is divided by x−6?
zheka24 [161]

Answer:

119

Step-by-step explanation:

Given f(x) divided by (x - h) then the value of f(h) is the remainder, thus

f(6) = 2(6)³ - 9(6)² + 11

     = 2(216) - 9(36) + 11

     = 432 - 324 + 11

     = 119 ← remainder

8 0
2 years ago
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