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OleMash [197]
3 years ago
11

Write a complete program that declares an integer variable, reads a value from the keyboard into that variable, and writes to st

andard output a single line containing the square of the variable's value. Besides the line and the number it contains, nothing else should be written to standard output.
Computers and Technology
1 answer:
Feliz [49]3 years ago
5 0

Answer:

// here is code in C++.

#include <bits/stdc++.h>

using namespace std;

// main function

int main()

{

  // variables

  double num;

  // read discriminant

  cin>>num;

  // calculate square of the input

  double result=num*num;

  // print the square number

  cout<<result<<endl;

     return 0;

}

Explanation:

Declare a variable "num".Read the value of "num" from keybord.Then calculate square of the input number.Print the square of input number.

Output:

5

25

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Write the definition of the function inputArray that prompts the user to input 20 numbers and stores the numbers into alpha. Wri
Alina [70]

Answer:

In Java:

public static  int[] inputArray(){

   Scanner input = new Scanner(System.in);

   int[] alpha = new int[20];

   for(int i = 0;i<20;i++){

       alpha[i] = input.nextInt();

   }

   return alpha;}

public static  int[] doubleArray(int [] alpha){

   int[] beta = new int[20];

   for(int i = 0;i<20;i++){

       beta[i] = 2 * alpha[i];

   }

   return beta;

}

public static int[] copyAlphaBeta(int [] alpha, int [] beta){

   int [] AlphaBeta = new  int[10];

   for(int i = 0;i<5;i++){

       AlphaBeta[i] = alpha[i];

   }

   int count = 5;

   for(int i = 15;i<20;i++){

       AlphaBeta[count] = beta[i];

       count++;

   }

   return AlphaBeta;

}

public static void printArray(int [] alpha){

   for(int i = 0;i<20;i++){

       System.out.print(alpha[i]+" ");

       if((i+1)%15 == 0){

           System.out.println(" ");

       }

   }

}

Explanation:

The inputArray is defined here

public static  int[] inputArray(){

   Scanner input = new Scanner(System.in);

This declares alpha array of 20 elements

   int[] alpha = new int[20];

The following iteration gets input from the user into the array

<em>    for(int i = 0;i<20;i++){</em>

<em>        alpha[i] = input.nextInt();</em>

<em>    }</em>

This returns the alpha array

   return alpha;}

The doubleArray is defined here. It takes the alpha array as its input parameter

public static  int[] doubleArray(int [] alpha){

This declares beta of 20 integers

   int[] beta = new int[20];

This populates beta by 2 * alpha[i]

<em>    for(int i = 0;i<20;i++){</em>

<em>        beta[i] = 2 * alpha[i];</em>

<em>    }</em>

This returns the alpha array

   return beta;}

The copyAlphaBeta array is defines here

public static int[] copyAlphaBeta(int [] alpha, int [] beta){

This declares AlphaBeta as 10 elements

   int [] AlphaBeta = new  int[10];

This populates the first 5 elements of AlphaBeta with the first 5 of alpha

<em>    for(int i = 0;i<5;i++){</em>

<em>        AlphaBeta[i] = alpha[i];</em>

<em>    }</em>

   int count = 5;

This populates the last 5 elements of AlphaBeta with the last 5 of beta

<em>    for(int i = 15;i<20;i++){</em>

<em>        AlphaBeta[count] = beta[i];</em>

<em>        count++;</em>

<em>    }</em>

This returns the AlphaBeta array

   return AlphaBeta;

}

The printArray is defined here. It takes the alpha array as its input parameter

public static void printArray(int [] alpha){

This iterates through alpha array

   for(int i = 0;i<20;i++){

This prints each element of the array

       System.out.print(alpha[i]+" ");

A new line is started after the 15th element

<em>        if((i+1)%15 == 0){</em>

<em>            System.out.println(" ");</em>

<em>        }</em>

   }

}

See attachment for complete program which includes the main

Download txt
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c. (speed + miles) * 3  = (10 + 5) * 3 = 15 * 3 = 45

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blagie [28]

Circles

Area of Circle is \pi d^{2} /4

Total percentage increase in the area of the modified circle is 69%

Explanation:

(a)  Given the diameter of the circle be d

Then the radius of the circle = r = d/2

and the area of the circle is given by:

 

Area(A) = \pi r^{2}  

A = \pi (d/2)^{2}

A = \pi d^{2} /4

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(b)

The increase in percentage while changing the dimensions is given by the formula  :

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Where ,

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Since a% = b%

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Given here the diameter of the circle increases by 30% so a =30

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