The software is written in C++ and may be found in the explanation section below. C++ keywords and symbols are all capitalized. The least number of all three integers is determined via a nested if-else decision branch. After you've entered three integers, the application prints the least of them all.
<h3>
What is the example of C++?</h3>
#include <iostream>
using namespace std;
int main() {
int num1,num2,num3;
cout<<"enter first integers"<<endl;
cin>>num1;
cout<<"enter second integers"<<endl;
cin>>num2;
cout<<"enter the third integers"<<endl;
cin>>num3;
if(num1<num2){
if(num1<num3){
cout<<"Smallest integer is "<<num1<<endl;
} else{
cout<<"Smallest integer is "<<num3<<endl;
}
}else {
if(num2<num3){
cout<<"Smallest integer is "<<num2<<endl;
} else{
cout<<"Smallest integer is "<<num3<<endl;
}
}
return 0;
}
Thus, it is written in C++ language.
For more details about C++ click here:
brainly.com/question/19581899
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Answer:see explanation
Explanation:
Hello, from your question I see that you need a program which based on countNum's value prints ready then all the numbers to 1 and finally go!, I'd appreciate if you provided information about the numbers after the example you gave as I do not know if they are to be printed too.
The solution I provide includes the countdown to 1 printing newline after each number and text. Try it out!
#include <stdio.h>
int main(void)
{
int countNum;
int i;
countNum = 22;
for ( i = countNum; i > 0; i--) {
if (i == countNum){
printf("Ready!\n");
}
printf("%d\n",i);
}
printf("Go!\n");
return 0;
}
Answer:
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