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Dafna1 [17]
3 years ago
5

Which protocol can be used to send ipv6 packets over an ipv4 network?

Computers and Technology
1 answer:
Mariana [72]3 years ago
4 0
There are three tunneling protocols. They are ISATAP, <span>teredo and 6TO4</span><span />
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NullPointerException and ArithmeticException are both derived from which class?
irina1246 [14]

Answer: c) Run-time Exception

Explanation: Runtime Exception is the exception that works in the JVM(Java Virtual Machine) as a super-class. It can also act during the general working of the JVM and are not checked by any resources. The exception that are followed from the Runtime exception is Arithmetic exception and  Null pointer exception as the subclass. Therefore ,the correct option is option(c).

3 0
4 years ago
Implement a function called merge that does the following in C#:
levacccp [35]

Answer:

Check the explanation

Explanation:

using System;

using System.Collections.Generic;

using System.Linq;

public class Problem2

{

public static IEnumerable<int> merge (IEnumerable<int> input1, IEnumerable<int> input2, IEnumerable<int> input3)

{

IList<int> list = new List<int>();

foreach (int i in input1)

{

if(i%3==0 && ! list.Contains(i))

list.Add(i);

}

foreach (int i in input2)

{

if(i%3==0 && ! list.Contains(i))

list.Add(i);

}

foreach (int i in input3)

{

if(i%3==0 && ! list.Contains(i))

list.Add(i);

}

return list;

}

}

public class Problem2Demo{

static void Main (string[] args)

{

Random rnd = new Random ();

var list1 = Enumerable.Range (1, 10).Select (i => (rnd.Next () % 15) + 1);

var list2 = Enumerable.Range (1, 10).Select (i => (rnd.Next () % 15) + 1);

var list3 = Enumerable.Range (1, 10).Select (i => (rnd.Next () % 15) + 1);

var answer = Problem2.merge (list1, list2, list3);

foreach (int i in answer)

{

Console.WriteLine (i);

}

}

Kindly check the attached output image below.

8 0
3 years ago
Create the following SQL Server queries that access the Northwind database. Place them in a zip file and place the zip file in t
neonofarm [45]

Answer:

1. SELECT e.EmployeeID, e.FirstName, e.LastName, COUNT(*) as OrderByEmployee FROM Employees e

JOIN Orders o

ON e.EmployeeID = o.EmployeeID

WHERE YEAR(o.OrderDate) = '1996'

GROUP BY e.EmployeeID,e.FirstName,e.LastName

ORDER BY OrderByEmployee DESC

2. SELECT o.OrderID,c.CustomerID, o.OrderDate,SUM((od.Quantity)*

od.UnitPrice - od.Discount)) as TotalCost FROM Orders o

JOIN [Order Details] od

ON od.OrderID = o.OrderID

JOIN Customers c

ON o.CustomerID = c.CustomerID

WHERE (MONTH(OrderDate)= 7 OR MONTH(OrderDate) = 8) and

YEAR(OrderDate) = 1996

GROUP BY o.OrderID,c.CustomerID, o.OrderDate

ORDER BY TotalCost DESC

3. SELECT c.CustomerID, c.CompanyName, c.City, COUNT(o.OrderID) as TotalOrder, SUM(od.Quantity* od.UnitPrice) as TotalOrderAmount FROM Customers c

JOIN Orders o

ON o.CustomerID = c.CustomerID

JOIN [Order Details] od

ON od.OrderID = o.OrderID

WHERE c.Country = 'USA'

GROUP BY c.CustomerID, c.CompanyName, c.City

ORDER BY c.City, c.CustomerID

4. SELECT c.CustomerID, c.CompanyName, c.City, COUNT(o.OrderID) as TotalOrder, SUM(od.Quantity* od.UnitPrice) as TotalOrderAmount FROM Customers c

JOIN Orders o

ON o.CustomerID = c.CustomerID

JOIN [Order Details] od

ON od.OrderID = o.OrderID

WHERE c.Country = 'USA'

GROUP BY c.CustomerID, c.CompanyName, c.City

HAVING COUNT(o.OrderID) > 3

ORDER BY c.City, c.CustomerID

5. SELECT p.ProductID, p.ProductName, s.ContactName as SupplierName, MAX(o.OrderDate) as LastOrderDateOfProduct FROM Products p

JOIN Categories c

ON c.CategoryID = p.CategoryID

JOIN Suppliers s

ON s.SupplierID = p.SupplierID

JOIN [Order Details] od

ON od.ProductID = p.ProductID

JOIN Orders o

ON o.OrderID = od.OrderID

where c.CategoryName = 'Grains/Cereals'

GROUP BY p.ProductID, p.ProductName, s.ContactName

ORDER BY SupplierName, p.ProductName

6. SELECT p.ProductID, p.ProductName, Count(DISTINCT c.CustomerID ) as OrderByThisManyDistinctCustomer

FROM Products p

JOIN [Order Details] od

ON od.ProductID = p.ProductID

JOIN Orders o

ON o.OrderID = od.OrderID

JOIN Customers c

ON c.CustomerID = o.CustomerID

where YEAR(o.OrderDate) = 1996

GROUP BY p.ProductID, p.ProductName

Explanation:

The six query statements returns data from the SQL server Northwind database. Note that all the return data are grouped together, this is done with the 'GROUP BY' Sql clause.

8 0
3 years ago
IS ANYONE ELSE JUST GETTING PPL PUTTING LINKS WHEN U ASK A QUESTION???
TiliK225 [7]
UGH IKR, LIKE JUST ANSWER THE FRICKIN QUESTION
4 0
3 years ago
Read 2 more answers
You have just read about a new security patch that has been made available for your Windows system, so you install the patch as
zhenek [66]

Answer:

A

Explanation:

The best action to take is to download and install the last good update; in that case, it will override the recent unstable update.

An update is not like a single program that can be add or remove from the control panel.

6 0
3 years ago
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