<h3>
Answer:</h3>
48
<h3>
Step-by-step explanation:</h3>
Let x represent the distance OC. Then CD = x+2, and DP = 16-x. The radius of circle P is ...
... CD +DP = (x+2) +(16-x) = 18
The radius of circle O is ..
... OC + CD = (x) + (x +2) = 2x+2
The length OP is ...
... OC + CP = (x) + (18) = x+18.
Now, the perimeter of ΔAOP is ...
... radius of circle O + radius of circle P + OP = 80
... = (2x+2) + 18 + (x+18) = 3x+38 = 80
Then x is ...
... x = (80 -38)/3 = 14
and the radius of circle O is
... 2x +2 = 2·14 +2 = 30
The desired sum is ...
... OB + BP = (radius of circle O) + (radius of circle P) = 30 + 18
... OB + BP = 48
