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rjkz [21]
3 years ago
7

Can somebody help me with this. Please see the attachment.

Mathematics
1 answer:
mr_godi [17]3 years ago
6 0
<h3>Answer:</h3>

48

<h3>Step-by-step explanation:</h3>

Let x represent the distance OC. Then CD = x+2, and DP = 16-x. The radius of circle P is ...

... CD +DP = (x+2) +(16-x) = 18

The radius of circle O is ..

... OC + CD = (x) + (x +2) = 2x+2

The length OP is ...

... OC + CP = (x) + (18) = x+18.

Now, the perimeter of ΔAOP is ...

... radius of circle O + radius of circle P + OP = 80

... = (2x+2) + 18 + (x+18) = 3x+38 = 80

Then x is ...

... x = (80 -38)/3 = 14

and the radius of circle O is

... 2x +2 = 2·14 +2 = 30

The desired sum is ...

... OB + BP = (radius of circle O) + (radius of circle P) = 30 + 18

... OB + BP = 48

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40 students prefer vanilla. To get this answer you need to multiply 200 times 0.2 because you are trying to find 20%
4 0
2 years ago
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How many words can be formed by using the W,X,Y,Z if repetitions is not allowed?
Setler [38]

Answer:

24

Step-by-step explanation:

What you have here is a permutation, seeing as each element can only be used once.

We have 4 letters initially, so we can choose any 1 as our first letter. We have 4 choices for our first letter

However, once we choose our first letter, we can't use it anymore, so, for our second letter, we can only choose from the remaining 3 letters.

Furthermore, once we choose our second letter, we can only choose our 3rd letter from the remaining two letters we didn't choose yet.

Finally, our last letter will always be the one we didn't choose the last 3 times. So there is only one choice here.

Going off of this, we have four choices for the 1st letter, three choices for the 2nd letter, two choices for the 3rd letter, and one choice for the 4th letter

The way to calculate how many permutations we have without repetition is using factorials

N!

Where N is the number of elements you have.

In this case, it would be 4!

4! is 4 * 3 * 2 * 1

Which equals 24

If you notice, each number in 4! is the number of options we have for each choice. 4, then 3, and so on

5 0
3 years ago
solve this system of linear equations. Separate the X- and Y- values with a comma. -9x+2y=-16 19x+3y=41​
Serjik [45]

Answer:

(2, 1)

Step-by-step explanation:

The best way to do this to avoid tedious fractions is to use the addition method (sometimes called the elimination method).  We will work to eliminate one of the variables.  Since the y values are smaller, let's work to get rid of those.  That means we have to have a positive and a negative of the same number so they cancel each other out.  We have a 2y and a 3y.  The LCM of those numbers is 6, so we will multiply the first equation by a 3 and the second one by a 2.  BUT they have to cancel out, so one of those multipliers will have to be negative.  I made the 2 negative.  Multiplying in the 3 and the -2:

3(-9x + 2y = -16)--> -27x + 6y = -48

-2(19x + 3y = 41)--> -38x - 6y = -82

Now you can see that the 6y and the -6y cancel each other out, leaving us to do the addition of what's left:

-65x = -130 so

x = 2

Now we will go back to either one of the original equations and sub in a 2 for x to solve for y:

19(2) + 3y = 41 so

38 + 3y = 41 and

3y = 3.  Therefore,

y = 1

The solution set then is (2, 1)

6 0
3 years ago
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fenix001 [56]

Answer:

First option is correct answer.

Step-by-step explanation:

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5 0
3 years ago
There are 550 cats in animal shelters in a particular county. A sample of 20 cats is taken and 12 of those cats are orange. How
lianna [129]
12÷20=0.6
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The answer is 330
Hope this helps!
3 0
3 years ago
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