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Alik [6]
3 years ago
11

Hello :)

Mathematics
2 answers:
nikdorinn [45]3 years ago
8 0

Answer:

B

Step-by-step explanation:

  • <em>Rule => f(x)=a , f⁻¹(a)=x</em>

So ; f⁻¹(5-x)=x

plug in ''-x+5'' for x

f⁻¹(5-x)=x

f⁻¹(5-(-x + 5))=-x + 5

f⁻¹(5 +x -5 )= -x  + 5

<em>f⁻¹(x)= 5 - x</em>

Hope this helps ^-^

Annette [7]3 years ago
5 0

Answer:

<h2>B) 5 - x</h2>

Step-by-step explanation:

\text{We have}\ f(x)=5-x\to y=5-x\\\\\text{exchange x to y:}\ x=5-y\\\\\text{Solve for y:}\\\\5-y=x\qquad\text{subtract 5 from both sides}\\\\-y=x-5\qquad\text{change the signs}\\\\y=-x+5\\\\y=5+(-x)\\\\y=5-x\to f^{-1}(x)=5-x

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Gnesinka [82]
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4 0
3 years ago
Suppose that the given line has a slope of -2/3 and a y-intercept of (0,5/3). which of the following points is also a solution t
otez555 [7]

Answer:

From five given points it is find that points (1 , 1) and (4 , -1) will apply

Step-by-step explanation:

According to question,

Slop of line (m) = \frac{-2}{3}

And y-intercept is ( 0, \frac{5}{3})

So from above slope and points, the equation of line can be written as

y = mx + c

i.e \frac{5}{3} = \frac{-2}{3} x + c

    \frac{5}{3} = \frac{-2}{3} (0) + c

    \frac{5}{3} = 0 + c

Or, c = \frac{5}{3}

A) With points ( 5, \frac{5}{3} )

   At x = 5, y =\frac{-2}{3} (5) + \frac{5}{3}

            or, y = \frac{-10}{3} + \frac{5}{3}

            so, y = \frac{-5}{3}

Hence this points do not apply

B) With points ( 1 , 1 )

   At x = 1, y =  \frac{-2}{3} (1) +  \frac{5}{3}

      or,      y =  \frac{-2+5}{3}

      So,     y =  \frac{3}{3}

                y = 1

Hence this points will apply

C) With points ( 4 , -1 )

    At x = 4 , y =  \frac{-2}{3} (4) +  \frac{5}{3}

                    y =  \frac{-8+5}{3}

                    y =  \frac{-3}{3}

             So,  y= -1

Hence this points will apply

D) With points (-3 ,7)

    At x = - 3, y = \frac{-2}{3} (-3) +  \frac{5}{3}

                     y = \frac{14}{3}

 Hence this point will not apply

E) with points (0 , 0)

    At x 0,     y =  \frac{-2}{3} (0) +  \frac{5}{3}

               Or, y = 0 +  \frac{5}{3}

                     y =  \frac{5}{3}

Hence this point will not apply

∴ From above five given points it is find that points (1 , 1) and (4 , -1) apply

Answer

7 0
3 years ago
I don’t understand this please help and thank you.
Marta_Voda [28]

Answer:

Step-by-step explanation:

Your b is -1 and your mx I don’t know how to figure that out but I helped with your variable b

4 0
4 years ago
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