2x² + 12x + 11 - (x - 4)²
2x² + 12x + 11 - 1(x - 4)²
2x² + 12x + 11 - 1(x - 4)(x - 4)
2x² + 12x + 11 - 1(x(x - 4) - 4(x - 4))
2x² + 12x + 11 - 1(x(x) - x(4) - 4(x) + 4(4))
2x² + 12x + 11 - 1(x² - 4x - 4x + 16)
2x² + 12x + 11 - 1(x² - 8x + 16)
2x² + 12x + 11 + 1(x²) + 1(8x) - 1(16)
2x² + 12x + 11 + x² + 8x - 16
2x² + x² + 12x + 8x + 11 - 16
3x² + 20x - 5
Let x = the number of nonzero digits in a randomly selected zip code. what are the possible values of x? (note: u.s. domestic zip codes have exactly five digits with at least two nonzero digits.)
Solution: The possible values of x are 2, 3, 4, 5. Hence the option 2,3,4,5 is correct.
Explanation:
We are given that U.S domestic zip-code consists of 5 digits and there zip-codes contains at least 2 non-zero digits. It means we can not see a zip-code with five zero's and a zip-code with four zero's.
Therefore, we can have zip-code containing 2 non-zero digits, 3 non-zero digits, 4 non-zero digits and 5 non-zero digits. Hence the possible values of x are 2,3,4,5
<span>Let's look at the information that you do have.
y = yellow
g = green
g + y = 38
</span><span>g = 38 - y
If there are 14 green skittles,then we know that:
</span>14 + y = 38
14 = 38 - y<span>
so, we can then do the equation:
38 - 14 = y
38 - 14 = 24
y = 24
</span>
So, the answer is 24 green skittles.