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Arlecino [84]
3 years ago
11

2.a)Find the prime factorizations of 90 and 168.

Mathematics
1 answer:
balu736 [363]3 years ago
4 0
90|2\\45|3\\15|3\\.\ 5|5\\.\ 1|\\\\90=2\cdot3\cdot3\cdot5\\\\168|2\\.\ 84|2\\.\ 42|2\\.\ 21|3\\.\ \ 7|7\\.\ \ 1|\\\\168=2\cdot2\cdot2\cdot3\cdot7

100|2\\.\ 50|2\\.\ 25|5\\.\ \ 5|5\\.\ \ 1|\\\\100=2\cdot2\cdot5\cdot5\\\\126|2\\.\ 63|3\\.\ 21|3\\.\ \ 7|7\\.\ \ 1|\\\\126=2\cdot3\cdot3\cdot7
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An ice sculpture is melting from the heat. it's height changes by -2/25 every hour, what will it be after 5 hours?
madreJ [45]

Answer:

  Height will have changed by -2/5

Step-by-step explanation:

change in height = (change in height/hour) × hours

  = (-2/25) × 5 = -2/5

7 0
3 years ago
<img src="https://tex.z-dn.net/?f=%20%5Cfrac%7By%7D%7B2%7D%20%20%3C%20%20-%203" id="TexFormula1" title=" \frac{y}{2} &lt; - 3"
Allisa [31]
Hey!


Okay, to solve this problem, we'd first have to multiply both sides by two. The reason we do this is to get y on its own.

<em>Original Equation : </em>
\frac{y}{2} < -3

<em>New Equation {Changed by Multiplying 2 on Both Sides} :</em>
\frac{2y}{2} < 2 ( -3 )

And we simplify the equation to get our answer.

<em>Old Equation :</em>
\frac{2y}{2} < 2 ( -3 )

<em>New Equation {Changed by Simplification} :</em>
y < -6

<em>So, the equation \frac{y}{2} < -3 simplified is</em>  y < -6.

Hope this helps!


- Lindsey Frazier ♥
8 0
2 years ago
If log 2 = a and log 5<br> b then<br> log<br> 32/125
sveta [45]

Answer:

log(32/125)

=log32 - log125 [log(x/y)=log(x) - log(y)]

=log(2)^2 - log(5)^3

=2log2-3log5 [log(x)^p=p log x]

=2a-3b

4 0
2 years ago
The voltage in a circuit is the product of two factors, the resistance and the current. If the voltage is 6ir + 15i + 8r+20, fin
andreev551 [17]

Answer:

  • resistance: (2r +5)
  • current: (3i +4)

Step-by-step explanation:

The factors of the given expression are ...

  6ir +15i +8r +20 = (3i +4)(2r +5)

Which factor is current and which is resistance is not clear. Usually, resistance is referred to using the variable r, so we suppose the expressions are supposed to be ...

  resistance: (2r +5)

  current: (3i +4)

4 0
3 years ago
Solve for x<br><br> 15x^2+16x= -4
Klio2033 [76]
15x²+16x+4 =0      (ax² +bx +c=0)

Δ = b²-4ac =256 - 4×15×4 =16

x1 = (-b+√Δ) / 2a = (-16+√16) / 30 =( -16+4) / 30 = -12/30 = - 2/5
x2 = (-b -√Δ) / 2a = (-16 -√16) / 30 = (-16 -4) /30 = -20/30 = -2/3
4 0
2 years ago
Read 2 more answers
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