Angela shared a cab with her friends. When they arrived at their destination, they evenly divided the

Given that ab = x, evaluate the following: c 2a3b+a2b+ab

Mrrafil [7]

It will be ......
.......

4 0

3 years ago

Which proportion could be used to solve

Brums [2.3K]

Answer:

Cups of carrot needed for 9 servings = 4.5 cups

Step-by-step explanation:

A recipe for sesame chicken calls for cup of chopped carrots

recipe 2 is for 4 servings

That is

2 cups of carrot = 4 servings

2 : 4

= 1 : 2

1 cup of carrot = 2 servings

how many cups of

carrots are needed for 9 servings?

Let x= number of carrot needed for 9 servings

1 : 2 = x : 9

1 /2 = x/ 9

Cross product

1*9 = 2*x

9=2x

Divide both sides by 2

9/2 = x

x= 4.5 Or 4 1/2

6 0

3 years ago

100% & There are 16 girls and 18 boys in a class. The teacher chooses a student's name at What is the probabilit

Mariulka [41]

Answer:a

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Julia evaluated the expression 3 to the third power plus 20 divided by 2 to the second power. What’s the answer need it tonight

nexus9112 [7]

Answer:

32

Step-by-step explanation:

8 0

3 years ago

Gibbs Baby Food Company wishes to compare the weight gain of infants using its brand versus its competitor’s. A sample of 40 bab

Leviafan [203]

Answer:

$z=\frac{(7.6-8.1)-0}{\sqrt{\frac{2.3^2}{40}+\frac{2.9^2}{55}}}}=-0.936$

The p value can be founded with this formula:

$p_v =P(z$

Since the p value is higher than the significance level provided of 0.05 we have enough evidence to FAIL to reject the null hypothesis and we can't conclude that the true mean for the Gibbs brand is significantly lower than the true mean for the competitor

Step-by-step explanation:

Information given

$\bar X_{1}=7.6$ represent the mean for Gibbs products

$\bar X_{2}=8.1$ represent the mean for the competitor

$\sigma_{1}=2.3$ represent the population standard deviation for Gibbs

$\sigma_{2}=2.9$ represent the sample standard deviation for the competitor

$n_{1}=40$ sample size for the group Gibbs

$n_{2}=55$ sample size for the group competitor

$\alpha=0.05$ Significance level provided

z would represent the statistic

Hypothesis to verify

We want to check if babies using the Gibbs brand gained less weight, the system of hypothesis would be:

Null hypothesis: $\mu_{1}-\mu_{2}=0$

Alternative hypothesis: $\mu_{1} - \mu_{2}< 0$

The statistic would be given by:

$z=\frac{(\bar X_{1}-\bar X_{2})-\Delta}{\sqrt{\frac{\sigma^2_{1}}{n_{1}}+\frac{\sigma^2_{2}}{n_{2}}}}$ (1)

Replacing the info given we got:

$z=\frac{(7.6-8.1)-0}{\sqrt{\frac{2.3^2}{40}+\frac{2.9^2}{55}}}}=-0.936$

The p value can be founded with this formula:

$p_v =P(z$

Since the p value is higher than the significance level provided of 0.05 we have enough evidence to FAIL to reject the null hypothesis and we can't conclude that the true mean for the Gibbs brand is significantly lower than the true mean for the competitor

5 0

3 years ago