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irga5000 [103]
3 years ago
7

50 PTS!!!

Mathematics
1 answer:
nydimaria [60]3 years ago
5 0

Answer:

the data of the cubic

as it the distance between the two integers closed under addition

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Factor completely: 3x2 + 2x - 1
Alex777 [14]
3x^{2}+2x-1=3x^{2}+3x-x-1= \\  \\ 3x(x+1)-(x+1)=(3x-1)(x+1)

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<em>"Associate with people who are likely to improve you."</em>
4 0
3 years ago
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PLS HELP WILL MARK BRAINLIESTTT What is the solution to this inequality?
vagabundo [1.1K]

Answer:

  a.  x > 0.2

Step-by-step explanation:

In either order, subtract the left-side constant and divide by the x-coefficient.

  3x +2.4 > 3

  3x > 0.6 . . . . . . subtract 2.4

  x > 0.2 . . . . . . . divide by 3

__

or

  x + 0.8 > 1 . . . . divide by 3

  x > 0.2 . . . . . . . subtract 0.8

8 0
3 years ago
1)A System of equations is shown below . What is the solution to the system of equations? 5x+2y=-15 2x-2y=-6
meriva

Answer:

x= -3 and y= 0

Step-by-step explanation:

5x+2y=-15

<u>2x-2y=-6     </u>

<u>7x        =-21</u>

x= -3

Putting value of x in equation 1  

5(-3) +2y=-15

-15+2y= -15

2y= 0

y= 0

This can be solved with the help of matrices

In matrix form the above equations can be written in the form

\left[\begin{array}{ccc}5&2\\2&-2\/\end{array}\right]  \left[\begin{array}{ccc}x\\y\\\end{array}\right]  = \left[\begin{array}{ccc}-15\\-6\\\end{array}\right]

Let

\left[\begin{array}{ccc}5&2\\2&-2\/\end{array}\right] = A  \left[\begin{array}{ccc}x\\y\\\end{array}\right]  = X  and  \left[\begin{array}{ccc}-15\\-6\\\end{array}\right]= B

Then AX= B

or X= A⁻¹ B

where  A⁻¹= adj A/ ║A║   where mod A≠ 0

adj A=  \left[\begin{array}{ccc}-2&-2\\-2&5\/\end{array}\right]

║A║= ( 5*-2- 2*2)= -10-4= -14≠0

X= A⁻¹ B

 \left[\begin{array}{ccc}x\\y\\\end{array}\right]    =- 1/14  \left[\begin{array}{ccc}-2&-2\\-2&5\/\end{array}\right]   \left[\begin{array}{ccc}-15\\-6\\\end{array}\right]

 \left[\begin{array}{ccc}x\\y\\\end{array}\right]    =- 1/14     \left[\begin{array}{ccc}-2*-15&+ -2*-6\\-2*-15&+ 5*-6\\\end{array}\right]

 \left[\begin{array}{ccc}x\\y\\\end{array}\right]  =- 1/14 \left[\begin{array}{ccc} 30&+12\\30&+-30\\\end{array}\right]

 \left[\begin{array}{ccc}x\\y\\\end{array}\right]  =- 1/14 \left[\begin{array}{ccc}42\\0\\\end{array}\right]

\left[\begin{array}{ccc}x\\y\\\end{array}\right]  = \left[\begin{array}{ccc}-42/14\\0/-14\\\end{array}\right]

\left[\begin{array}{ccc}x\\y\\\end{array}\right]  = \left[\begin{array}{ccc}-3\\0\\\end{array}\right]

From here x= -3 and y= 0

Solution Set = [(-3,0)]

3 0
3 years ago
HELP I HAVE TO FINISH THIS FAST
Usimov [2.4K]

Answer:

13 minus 3x cubed

Step-by-step explanation:

6 0
3 years ago
Solve for x <br> 4x - 3 =17
MakcuM [25]

Answer:

x = 5

Step-by-step explanation:

Add three to 17 and your answer will be 20, then divide 20 and 4 and your answer is 5

8 0
3 years ago
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