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Mekhanik [1.2K]
2 years ago
10

Write the slope intercept equation of a line that has a 3 slope of 5 & y-intercept of (0, –4). y =​

Mathematics
1 answer:
Karo-lina-s [1.5K]2 years ago
3 0
If the question is asking what the equation is when the slope is 5 then the equation will be y=5x-4 since the stem of the equation is going to be y=mx+b, m is the slope and b is the y intercept
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F(3) if f(x) = 2x + 4
Sliva [168]
It would be 10
You substitute “x”for “3” so the equation would be 2(3) + 4. Then you multiply 2 and 3, which is 6. Finally add the 4 to get 10.
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In your own words describe surface and area
Oksana_A [137]

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Hi there!

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8 0
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If a quadratic equation has a real root, what do you know about the other roots of the equation? Explain.
notsponge [240]

Answer:

A Quadratic Equation can have upto 2 roots maximum. So,if one of the roots is a Real number, there are following two possibilities:

1) The other root is also a real number, but a different number

2) Its a repeated root, so the other root is the same number.

The other root cannot be a complex number as its not possible for one root to be real and other to be complex. Either no root will be complex or both will be complex roots.

Following are 3 possibilities for the roots of a quadratic equation:

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7 0
3 years ago
What are the roots of the polynomial equation 3x^4+12x^2=6x^3
Dominik [7]
Factor the equation to give
3x^4+12x^2=6x^3
3x^4+12x^2-6x^3=0
x^2(3x^2+12-6x)=0
By the zero product property, either x^2=0 or (3x^2+12-6x)=0 or both.
If x^2=0, then x=0
if (3x^2+12-6x)=0, we use the quadratic formula to solve for x
where x=1 ± √ (3) i

Answer: the roots of <span>3x^4+12x^2=6x^3 are {0 (multiplicity 2), 1+&radic;3 i, 1-&radic;3 i}</span>
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