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3 years ago

Question is in the picture please help and if u have smart remarks dont reply ill report

Mathematics

1 answer:

emmasim [6.3K]3 years ago

8 0

Answer: Choice D

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Explanation:

It might help to turn the image sideways so that it is rotated 90 degrees. Have the triangle facing upward with (x1,y2) and (x1,y1) as the base points. The base has a length of (y2-y1) as this is the difference of y coordinate values. The x coordinate being the same indicates we simply subtract.

The height is (x3-x1) which is the difference of the x coordinates for either left point and the right point

So,
area = (1/2)*base*height
area = (1/2)*(y2-y1)*(x3-x1)
which is why choice D is the answer

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Slope of (0,45) (6,33) (15,15)

Vladimir [108]

Answer:

The slope is -2

Step-by-step explanation:

Given

$(x_1,y_1) = (0,45)$

$(x_2,y_2) = (6,33)$

$(x_2,y_3) = (15,15)$

Required

The slope (m)

Slope is calculated as:

$m = \frac{y_2 -y_1}{x_2 - x_1}$

So, we have:

$m = \frac{33 -45}{6 - 0}$

$m = \frac{-12}{6}$

$m =-2$

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3 years ago

Miriam and Salina are twins and their sister Rohana is 2 years older than them. The total of their ages is 32years .Find their a

Fudgin [204]

Answer:

644

Step-by-step explanation:

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3 years ago

A marketing researcher wants to find a 96% confidence interval for the mean amount those visitors spend per person per day while

ki77a [65]

Answer:

$n=(\frac{2.054(12)}{4})^2 =37.97 \approx 38$

So then the minimum sample to ensure the condition given is n= 38

Step-by-step explanation:

Notation

$\bar X$ represent the sample mean for the sample

$\mu$ population mean (variable of interest)

$\sigma=12$ represent the population standard deviation

n represent the sample size

ME = 4 the margin of error desired

Solution to the problem

When we create a confidence interval for the mean the margin of error is given by this formula:

$ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (a)

And on this case we have that ME =4 and we are interested in order to find the value of n, if we solve n from equation (a) we got:

$n=(\frac{z_{\alpha/2} \sigma}{ME})^2$ (b)

The critical value for 96% of confidence interval now can be founded using the normal distribution. The significance is $\alpha=1-0.96 =0.04$ . And in excel we can use this formula to find it:"=-NORM.INV(0.02;0;1)", and we got $z_{\alpha/2}=2.054$ , replacing into formula (b) we got:

$n=(\frac{2.054(12)}{4})^2 =37.97 \approx 38$

So then the minimum sample to ensure the condition given is n= 38

5 0

3 years ago

The U.S. Census Bureau conducts annual surveys to obtain information on the percentage of the voting-age population that is regi

yan [13]

Answer:

We conclude that the percentage of employed workers who have registered to vote exceeds the percentage of unemployed workers who have registered to vote.

Step-by-step explanation:

We are given that 513 employed persons and 604 unemployed persons are independently and randomly selected, and that 287 of the employed persons and 280 of the unemployed persons have registered to vote.

Let $p_1$ = percentage of employed workers who have registered to vote.

$p_2$ = percentage of unemployed workers who have registered to vote.

So, Null Hypothesis, $H_0$ : $p_1\leq p_2$ {means that the percentage of employed workers who have registered to vote does not exceeds the percentage of unemployed workers who have registered to vote}

Alternate Hypothesis, $H_A$ : $p_1>p_2$ {means that the percentage of employed workers who have registered to vote exceeds the percentage of unemployed workers who have registered to vote}

The test statistics that would be used here Two-sample z test for proportions;

T.S. = $\frac{(\hat p_1-\hat p_2)-(p_1-p_2)}{\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+\frac{\hat p_2(1-\hat p_2)}{n_2} } }$ ~ N(0,1)

where, $\hat p_1$ = sample proportion of employed workers who have registered to vote = $\frac{287}{513}$ = 0.56

$\hat p_2$ = sample proportion of unemployed workers who have registered to vote = $\frac{280}{604}$ = 0.46

$n_1$ = sample of employed persons = 513

$n_2$ = sample of unemployed persons = 604

So, the test statistics = $\frac{(0.56-0.46)-(0)}{\sqrt{\frac{0.56(1-0.56)}{513}+\frac{0.46(1-0.46)}{604} } }$

= 3.349

The value of z test statistics is 3.349.

Now, at 0.05 significance level the z table gives critical value of 1.645 for right-tailed test.

Since our test statistic is more than the critical value of z as 3.349 > 1.645, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that the percentage of employed workers who have registered to vote exceeds the percentage of unemployed workers who have registered to vote.

5 0

3 years ago

In rectangle MNOP, MO = 4x - 10 and NP = 2x + 4. What is the length of a diagonal?

slega [8]

Answer:

Step-by-step explanation:

From the rectangle, M O = NP

4x - 10 = 2x+4

4x-2x = 4 + 10

2x = 14

x = 14/2

x = 7

SInce MO and NP are the diagonal

Length of diagonal = 4x- 10

Length of diagonal = 4(7) - 10

Length of diagonal = 28 - 10

Length of diagonal = 18

hence the required length is 18

6 0

3 years ago