Answer:
7.
Solution given;
male=15
female=27
1st term=5*3
2nd term=3*3*3
now
Highest common factor=3
So
<u>The</u><u> </u><u>maximum</u><u> </u><u>number</u><u> </u><u>of</u><u> </u><u>groups</u><u> </u><u>that</u><u> </u><u>the</u><u> </u><u>teacher</u><u> </u><u>can</u><u> </u><u>make</u><u> </u><u>is</u><u> </u><u>3</u><u>.</u>
<u>and</u><u> </u><u>each</u><u> </u><u>team</u><u> </u><u>contains</u><u> </u><u>5</u><u> </u><u>male and</u><u> </u><u>9</u><u> </u><u>female</u><u>.</u>
Answer:
3,000,000,000
60,000,000
66,000
900
Step-by-step explanation:
3,060,066,900
:)I dont know is C
Answer:
Its A because when you do (x-5)=0 you add 5 to get x=5 and thats your x value and the 3 for your k is your y value
If 24 students went on a field trip, and 24 students represented eight tenths of the class, then

.
First, multiply by 10 on both sides.
240 = 8x
Divide by 8 on both sides.
x = 30.
The class has 30 students in all.
This is, however, only the equation way to solve.
Complete question :
A zoologist is interested in whether climate affects how high kangaroos can jump. In a random sample of gray kangaroos from an Australian forest, he found the mean jump height was x¯=286 inches with a margin of error of 15 inches.
Construct a confidence interval for the mean jump height of gray kangaroos.
Answer:
(271, 301)
Step-by-step explanation:
Given that:
Mean (x¯) = 286
Margin of Error = 15 inches
The confidence interval :
(Mean - Margin of Error), (mean + margin of error)
(286 - 15), (286 + 15)
(271, 301)
Hence confidence interval equals : (271, 301)