195xy is ur lowest common denominator
Answer:
7
Step-by-step explanation:
M = (L + S)
24/2 = 12
12-5 =7
L:5
S:7
7+5 = 12 (Manjit)
12+12= 24
Answer:
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10th
Maths
Pair of Linear Equations in Two Variables
Algebraic Solution of a Pair of Linear Equations
Solve: 3x + 4y = 10,2x - 2y...
MATHS
Asked on December 27, 2019 byShweta Rudravaram
Solve: 3x+4y=10,2x−2y=2 by the method of elimination.
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ANSWER
3x+4y=10 …………..(1)
2x−2y=2 (or) x−y=1 …………(2)
(1) ⇒(3x+4y=10)1
(2) ⇒(x−y=1)3
_____________________
3x+4y=10
3x−3y=3
_____________________
7y=7
∴y=1
Put y=1 in (1) we get 3x+4×1=10
3x=10−4=6
∴x=36=2
Hence x=2,y=1.
Answer:
Step-by-step explanation:
Find two linear functions p(x) and q(x) such that (p (f(q(x)))) (x) = x^2 for any x is a member of R?
Let p(x)=kpx+dp and q(x)=kqx+dq than
f(q(x))=−2(kqx+dq)2+3(kqx+dq)−7=−2(kqx)2−4kqx−2d2q+3kqx+3dq−7=−2(kqx)2−kqx−2d2q+3dq−7
p(f(q(x))=−2kp(kqx)2−kpkqx−2kpd2p+3kpdq−7
(p(f(q(x)))(x)=−2kpk2qx3−kpkqx2−x(2kpd2p−3kpdq+7)
So you want:
−2kpk2q=0
and
kpkq=−1
and
2kpd2p−3kpdq+7=0
Now I amfraid this doesn’t work as −2kpk2q=0 that either kp or kq is zero but than their product can’t be anything but 0 not −1 .
Answer: there are no such linear functions.
g(x) = -3x² - 2x + 3
g(-2) = -3(-2)² - 2(-2) + 3
g(-2) = -12 + 4 + 3 = -5
