What is the difference of the polynomials? (–2x3y2 + 4x2y3 – 3xy4) – (6x4y – 5x2y3 – y5)

2 answers:

4 0

For the answer to the question above, I'll provide my solutions to my answers for the problem below.

(–2x3y2 + 4x2y3 – 3xy4) – (6x4y – 5x2y3 – y5)

(−2x3)(y2)+4x2y3+−3xy4+−1(6x4y)+−1(−5x2y3)+−1(−y5)

(−2x3)(y2)+4x2y3+−3xy4+−6x4y+5x2y3+y5

−2x3y2+4x2y3+−3xy4+−6x4y+5x2y3+y5

−2x3y2+4x2y3+−3xy4+−6x4y+5x2y3+y5

(−6x4y)+(−2x3y2)+(4x2y3+5x2y3)+(−3xy4)+(y5)

−6x4y+−2x3y2+9x2y3+−3xy4+y5
So the answer is,
= −6x4y−2x3y2+9x2y3−3xy4+y5

I hope this helps

AnnZ [28]3 years ago

3 1

Answer:

$-2x^3y^2 + 9x^2y^3 -3xy^4 -6x^4y + y^5$

Step-by-step explanation:

Like terms are those terms which have same variables and have same powers.

To find the difference of the polynomials:

$(-2x^3y^2 + 4x^2y^3 -3xy^4) - (6x^4y -5x^2y^3 - y^5)$

Remove the bracket:

$-2x^3y^2 + 4x^2y^3 -3xy^4 -6x^4y + 5x^2y^3 + y^5$

Combine like terms, we have;

$-2x^3y^2 + 9x^2y^3 -3xy^4 -6x^4y + y^5$

Therefore, the difference of the given polynomials is, $-2x^3y^2 + 9x^2y^3 -3xy^4 -6x^4y + y^5$

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) find a vector parallel to the line of intersection of the planes 5x − y − 6z = 0 and x + y + z = 1.

snow_tiger [21]

The cross product of the normal vectors of two planes result in a vector parallel to the line of intersection of the two planes.

Corresponding normal vectors of the planes are
<5,-1,-6> and <1,1,1>

We calculate the cross product as a determinant of (i,j,k) and the normal products

i j k
5 -1 -6
1 1 1

=(-1*1-(-6)*1)i -(5*1-(-6)1)j+(5*1-(-1*1))k
=5i-11j+6k
=<5,-11,6>

Check orthogonality with normal vectors using scalar products
(should equal zero if orthogonal)
<5,-11,6>.<5,-1,-6>=25+11-36=0
<5,-11,6>.<1,1,1>=5-11+6=0

Therefore <5,-11,6> is a vector parallel to the line of intersection of the two given planes.

5 0

3 years ago

How does product (result) of (a-b)2 compare the product (a+b)

____ [38]

I'm assuming you mean (a-b)^2 : (a+b)^2

a^2 + b^2 cancel out leaving

-2ab versus +2ab

Therefore (a+b)^2 is +4ab greater.

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3 years ago

A new roller coaster at an amusement park requires individuals to be at least 4' 8" (56 inches) tall to ride. It is estimated

Maksim231197 [3]

Answer:

a) 34.46% of 10-year-old boys is tall enough to ride this coaster.

b) 78.81% of 10-year-old boys is tall enough to ride this coaster

c) 44.35% of 10-year-old boys is tall enough to ride the coaster in part b but not tall enough to ride the coaster in part a

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

$\mu = 54, \sigma = 5$