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Ket [755]
3 years ago
6

PLS HELP. 20 PTS.

Mathematics
1 answer:
Mashutka [201]3 years ago
6 0
180°=2x+10x+12
180=12x+12
168=12x
x=14

angle J=2x
J=2(14)
J=24

angle K=10x+12
K=10(14)+12
K=140+12
K=152
therefore, answer is C.

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svetoff [14.1K]
\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\\\
% left side templates
\begin{array}{llll}
f(x)=&{{  A}}({{  B}}x+{{  C}})+{{  D}}
\\ \quad \\
y=&{{  A}}({{  B}}x+{{  C}})+{{  D}}
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--------------------\\\\

\bf % template detailing
\bullet \textit{ stretches or shrinks horizontally by  } {{  A}}\cdot {{  B}}\\\\
\bullet \textit{ flips it upside-down if }{{  A}}\textit{ is negative}
\\\\
\bullet \textit{ horizontal shift by }\frac{{{  C}}}{{{  B}}}\\
\left. \qquad  \right. if\ \frac{{{  C}}}{{{  B}}}\textit{ is negative, to the right}\\\\
\left. \qquad  \right.  if\ \frac{{{  C}}}{{{  B}}}\textit{ is positive, to the left}\\\\

\bf \bullet \textit{ vertical shift by }{{  D}}\\
\left. \qquad  \right. if\ {{  D}}\textit{ is negative, downwards}\\\\
\left. \qquad  \right. if\ {{  D}}\textit{ is positive, upwards}\\\\
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now, with that template in mind, let's see

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\begin{array}{llll}
y=(&1x&-0)^2\\
&B&C
\end{array}

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Read 2 more answers
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DerKrebs [107]

Answer:

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