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3 years ago

What is the result when 4x2 + 7x − 5 is subtracted from 9x2 − 2x + 3?

Mathematics

2 answers:

Salsk061 [2.6K]3 years ago

6 0

Answer:

-10 + 9x - 8

Step-by-step explanation:

4x2 + 7x - 5 subtracted from

9x2 -2x + 3

8 + 7x - 5

18 - 2x + 3

(8-18) (+7x - -2x) (-5 - +3)

-10 ( +7x +2x) (-5-3)

-10 + 9x -8

Greeley [361]3 years ago

5 0

The answer is -9x

If you want explanation let me know!

I didn't provide one since you said ''What is the result''

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Under a dilation with center P and scale factor k, A' is the image of A. What is the value of k if PA = 7, and PA' = 28?

serg [7]

Can i please get the equation so i can solve it

I will edit this after you put it

Ignore this \/

Under a dilation with center P and scale factor k, A' is the image of A. What is the value of k if PA = 7, and PA' = 28

Under a dilation with center P and scale factor k, A' is the image of A. What is the value of k if PA = 7, and PA' = 28?Under a dilation with center P and scale factor k, A' is the image of A. What is the value of k if PA = 7, and PA' = 28?Under a dilation with center P and scale factor k, A' is the image of A. What is the value of k if PA = 7, and PA' = 28?Under a dilation with center P and scale factor k, A' is the image of A. What is the value of k if PA = 7, and PA' = 28?Under a dilation with center P and scale factor k, A' is the image of A. What is the value of k if PA = 7, and PA' = 28?Under a dilation with center P and scale factor k, A' is the image of A. What is the value of k if PA = 7, and PA' = 28?Under a dilation with center P and scale factor k, A' is the image of A. What is the value of k if PA = 7, and PA' = 28?Under a dilation with center P and scale factor k, A' is the image of A. What is the value of k if PA = 7, and PA' = 28?Under a dilation with center P and scale factor k, A' is the image of A. What is the value of k if PA = 7, and PA' = 28?

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3 years ago

A biologist is studying the growth of a particular species of algae. She writes the fall inclusion to show the radius of the alg

horrorfan [7]

Answer:

Part A)

A reasonable domain to plot the growth function is:

$0\leq d \leq 12$

Part B)

The y-intercept represents that when the biologist started her study, the radius of the algae was five millimeters.

Part C)

The average rate of change from d = 4 to d = 11 was about 0.11. This means that from the 4th day to the 11th, the radius of the algae grew, on average, at a rate of 0.11 mm per day.

Step-by-step explanation:

The radius of the algae f(d) in millimeters after d days is given by the function:

$f(d)=5(1.02)^d$

Part A)

We know that the radius of the algae was approximately 6.34 mm when the biologist concluded her study. To find the reasonable domain, we can substitute 6.34 for f(d) and solve for d. Therefore:

$6.34=5(1.02)^d$

Divide both sides by five:

$(1.02)^d=1.268$

Take the log of both sides with base 1.02:

$\displaystyle d=\log_{1.02}1.268$

Using the Change of Base Property, evaluate for d:

$\displaystyle d=\frac{\log 1.268}{\log 1.02}=11.9903...\approx 12$

So, the biologist concluded her study after 12 days.

Therefore, a reasonable domain to plot the growth function is:

$0\leq d\leq 12$

Part 2)

The y-intercept of the function is when d = 0. Find the y-intercept:

$f(0)=5(1.02)^{(0)}=5(1)=5$

Since d represent the amount of days after the study had begun, the y-intercept represents the radius of the algae on the initial day.

So, when the biologist started her study, the radius of the algae was five millimeters.

Part 3)

To find the average rate of change for a nonlinear function, we find the slope between the two endpoints on the interval.

We want to find the average rate of change of f(d) from d = 4 to d = 11.

Find the endpoints:

$f(4)=5.4121...\text{ and } f(11)=6.2168...$

And find the slope between them:

$\displaystyle m=\frac{f(11)-f(4)}{11-4}=0.1149...\approx 0.11$

Since f(d) measures millimeters and d measures days, this tells us that, on average, the radius of the algae grew by about 0.11 mm per day from the 4th day to the 11th day.

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2 years ago

Please help! question attached

Svetradugi [14.3K]

Answer:

36. y=x

37. x=4

38. y=3x-10

39. y=-25x+49

40. $y=-\dfrac{1}{18}x-\dfrac{89}{18}$

41. y=-x+3

Step-by-step explanation:

36. Parallel lines have the same slope. The slope of the line $y=x+42$ is $m=1,$ so the equation of a parallel line is

$y=x+b$

This line passes through the point (2,2), so its coordinates satisfy the equation:

$2=2+b\\ \\b=0$

and the equation of the line is $y=x$

37. The line $x=03$ is vertical ine, so parallel line is also vertical line with equation $x=a.$ Substitute the coordinates of the point (4,3):

$4=a$

hence the equation is $x=4$

38. Parallel lines have the same slope. The slope of the line $y=3x+24$ is $m=3,$ so the equation of a parallel line is

$y=3x+b$

This line passes through the point (2,-4), so its coordinates satisfy the equation:

$-4=3\cdot 2+b\\ \\b=-10$

and the equation of the line is $y=3x-10$

39. Parallel lines have the same slope. The slope of the line $y=-25x+35$ is $m=-25,$ so the equation of a parallel line is

$y=-25x+b$

This line passes through the point (2,-1), so its coordinates satisfy the equation:

$-1=-25\cdot 2+b\\ \\b=49$

and the equation of the line is $y=-25x+49$

40. Perpendicular lines have slopes satisfying $m_1\cdot m_2=-1$ Since the line $y=18x+26$ has the slope $m_1=18,$ perpendicular line has the slope $m_2 =-\dfrac{1}{18}.$

The equation is

$y=-\dfrac{1}{18}x+b$

This line passes through the point (1,-5), so its coordinates satisfy the equation:

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and the equation of the line is $y=-\dfrac{1}{18}x-\dfrac{89}{18}$

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The equation is

$y=-x+b$

This line passes through the point (4,-1), so its coordinates satisfy the equation:

$-1=-4+b\\ \\b=3$

and the equation of the line is $y=-x+3$

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Over [174]

When somebody is reading numbers from a book
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