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poizon [28]
3 years ago
8

A pink crayon is made with 12\text{ mL}12 mL12, space, m, L of red wax for every 5\text{ mL}5 mL5, space, m, L of white wax. Whi

ch of the following wax mixtures will create the same shade of pink?
Mathematics
1 answer:
Sedaia [141]3 years ago
4 0

Answer:

D 36 ML of red wax mixed with 15 ML of white wax AND

E 60 ML of red wax mixed with 25 ML of white wax

Step-by-step explanation:

just listen to me im big brain

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Step-by-step explanation:

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An author released his book on May 1. His daily sales steadily increased until they peaked and then steadily declined. He found
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The domain of a certain function are all possible values of x that are applicable to the function or can make the function true. For this certain function, the domain is from the time that the book was released to the time that the sales was also zero due to steady decline in sales. 
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The figure shown below is a rhombus. Give the angle value (numerical, not the letters.
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90 deg

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Recall that for a rhombus, the diagonals always intersect at right angles.

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Nina has 3 feet ribbon that she wants to cut into 8 equal sized pieces. What is true about the length of each ribbon? A) each pi
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If a coin is tossed three times, find probability of getting
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{\large{\textsf{\textbf{\underline{\underline{Given :}}}}}}

‣ A coin is tossed three times.

{\large{\textsf{\textbf{\underline{\underline{To \: Find :}}}}}}

‣ The probability of getting,

1) Exactly 3 tails

2) At most 2 heads

3) At least 2 tails

4) Exactly 2 heads

5) Exactly 3 heads

{\large{\textsf{\textbf{\underline{\underline{Using \: Formula :}}}}}}

\star \: \tt  P(E)= {\underline{\boxed{\sf{\red{  \dfrac{ Favourable \:  outcomes }{Total \:  outcomes}  }}}}}

{\large{\textsf{\textbf{\underline{\underline{Solution :}}}}}}

★ When three coins are tossed,

then the sample space = {HHH, HHT, THH, TTH, HTH, HTT, THT, TTT}

[here H denotes head and T denotes tail]

⇒Total number of outcomes \tt [ \: n(s) \: ] = 8

<u>1) Exactly 3 tails </u>

Here

• Favourable outcomes = {HHH} = 1

• Total outcomes = 8

\therefore  \sf Probability_{(exactly  \: 3 \:  tails)}  =  \red{ \dfrac{1}{8}}

<u>2) At most 2 heads</u>

[It means there can be two or one or no heads]

Here

• Favourable outcomes = {HHT, THH, HTH, TTH, HTT, THT, TTT} = 7

• Total outcomes = 8

\therefore  \sf Probability_{(at \: most  \: 2 \:  heads)}  =  \green{ \dfrac{7}{8}}

<u>3) At least 2 tails </u>

[It means there can be two or more tails]

Here

• Favourable outcomes = {TTH, TTT, HTT, THT} = 4

• Total outcomes = 8

\longrightarrow   \sf Probability_{(at \: least \: 2 \:  tails)}  =  \dfrac{4}{8}

\therefore  \sf Probability_{(at \: least \: 2 \:  tails)}  =   \orange{\dfrac{1}{2}}

<u>4) Exactly 2 heads </u>

Here

• Favourable outcomes = {HTH, THH, HHT } = 3

• Total outcomes = 8

\therefore  \sf Probability_{(exactly \: 2 \:  heads)}  =  \pink{ \dfrac{3}{8}}

<u>5) Exactly 3 heads</u>

Here

• Favourable outcomes = {HHH} = 1

• Total outcomes = 8

\therefore  \sf Probability_{(exactly \: 3 \:  heads)}  =  \purple{ \dfrac{1}{8}}

\rule{280pt}{2pt}

8 0
1 year ago
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