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Dafna11 [192]
3 years ago
7

What is a asteroid belt,

Mathematics
1 answer:
grandymaker [24]3 years ago
5 0

Answer:

The asteroid belt is a torus-shaped region in the Solar System, located roughly between the orbits of the planets Jupiter and Mars, that is occupied by a great many solid, irregularly shaped bodies, of many sizes but much smaller than planets, called asteroids or minor planets

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What is the measurement of the longest line segment in a right rectangular prism that is 26 inches long, 2 inches wide, and 2 in
EastWind [94]

Answer:

6\sqrt{19} \approx 26.153 inches.

Step-by-step explanation:

The longest line segment in a right rectangular prism is the diagonal that connects two opposite vertices. On the first diagram attached, the green line segment connecting A and G is one such diagonals. The goal is to find the length of segment \mathsf{AG}.

In this diagram (not to scale,) \mathsf{AB} = 26 (length of prism,) \mathsf{AC} = 2 (width of prism,) \mathsf{AE} = 2 (height of prism.)

Pythagorean Theorem can help find the length of \mathsf{AG}, one of the longest line segments in this prism. However, note that this theorem is intended for right triangles in 2D, not the diagonal in a 3D prism. The workaround is to simply apply this theorem on two different right triangles.

Start by finding the length of line segment \mathsf{AD}. That's the black dotted line in the diagram. In right triangle \triangle\mathsf{ABD} (second diagram,)

  • Segment \mathsf{AD} is the hypotenuse.
  • One of the legs of \triangle\mathsf{ABD} is \mathsf{AB}. The length of \mathsf{AB} is 26, same as the length of this prism.
  • Segment \mathsf{BD} is the other leg of this triangle. The length of \mathsf{BD} is 2, same as the width of this prism.

Apply the Pythagorean Theorem to right triangle \triangle\mathsf{ABD} to find the length of \mathsf{AB}, the hypotenuse of this triangle:

\mathsf{AD} = \sqrt{\mathsf{AB}^2 + \mathsf{BD}^2} = \sqrt{26^2 + 2^2}.

Consider right triangle \triangle \mathsf{ADG} (third diagram.) In this triangle,

  • Segment \mathsf{AG} is the hypotenuse, while
  • \mathsf{AD} and \mathsf{DG} are the two legs.

\mathsf{AD} = \sqrt{26^2 + 2^2}. The length of segment \mathsf{DG} is the same as the height of the rectangular prism, 2 (inches.) Apply the Pythagorean Theorem to right triangle \triangle \mathsf{ADG} to find the length of the hypotenuse \mathsf{AG}:

\begin{aligned}\mathsf{AG} &= \sqrt{\mathsf{AD}^2 + \mathsf{GD}^2} \\ &= \sqrt{\left(\sqrt{26^2 + 2^2}\right)^2 + 2^2}\\ &= \sqrt{\left(26^2 + 2^2\right) + 2^2} \\&= 6\sqrt{19} \\&\approx 26.153\end{aligned}.

Hence, the length of the longest line segment in this prism is 6\sqrt{19} \approx 26.153 inches.

5 0
3 years ago
Change 2.56 into a percentage *<br><br> 0.0256%<br> 25.6%<br> 256.0%<br> none of the above
Ksivusya [100]

Answer:

C: 256%

Step-by-step explanation:

8 0
2 years ago
Read 2 more answers
Hhhehdhdhdd dbdhshshsnnsmemsiskzmdbbdhdhdhdbdb sbdb
Ne4ueva [31]

Answer:

Please what are you trying to say

3 0
3 years ago
Factor completely 6n^2-18n
lubasha [3.4K]
6n^2-18n

1.find your GCF
 "6n"

final answer;
6n(n-3)
8 0
3 years ago
L varies directly with the square of Z. L is 12 when Z is 2. Find the value of L when Z is 4.
kow [346]

Answer:

L = 48

Step-by-step explanation:

Given that L varies directly with Z² , then the equation relating them is

L = kZ² ← k is the constant of variation

To find k use the condition L = 12 when Z = 2 , then

12 = k × 2² = 4k ( divide both sides by 4 )

3 = k

L = 3Z² ← equation of variation

When Z = 4 , then

L = 3 × 4² = 3 × 16 = 48

7 0
3 years ago
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