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melisa1 [442]
3 years ago
10

A painter is hired to paint the interior walls of a large warehouse. The function f(x)=20,000−40x models the area in square feet

that remain to be painted, where x represents the number of minutes the painter has worked from the 100-minute mark through the 200-minute mark of the project.
What is the practical range of the function?

A) all integers

B) all real numbers between 100 and 200 inclusive

C) all real numbers between 12,000 and 16,000 inclusive

D) integers from 100 to 200 inclusive
Mathematics
2 answers:
Lapatulllka [165]3 years ago
6 0

Answer:

Option C.

Step-by-step explanation:

The given function is

f(x)=20000-40x

where x represents the number of minutes the painter has worked from the 100-minute mark through the 200-minute mark of the project.

We need to find the practical range of the function.

The value of x lies from 100 to 200.

At x=100,

f(100)=20000-40(100)=20000-4000=16000

At x=200,

f(200)=20000-40(200)=20000-8000=12000

It means the practical range of the function is all real numbers between 12,000 and 16,000 inclusive.

Hence, the correct option is C.

Leto [7]3 years ago
4 0

Insert x = 100 and x = 200 in the function

f(100) = 20,000 - 40*100

= 20,000 - 4000

= 16,000


f(2)) = 20,000 - 8,000 = 12,000

So its choice C  ,  All reals between 12,000 and 16,000 inclusive.

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Which is a graph for the inequality m < -2 ?
aliya0001 [1]

Answer:

B

Step-by-step explanation:

This answer shows values of -2, and less than -2

6 0
3 years ago
Write a rule for the nth term of the sequence 2,20,50,92?
Tomtit [17]

Answer:

482

Step-by-step explanation:

Their 2nd difference is 12

7 0
3 years ago
Read 2 more answers
I round to 900 I have twice as many hundreds as ones and all my digits are different but their sums are 18 can someone answer th
stellarik [79]

Answer:

The number of once is 9.1  

The number of hundreds is 8.9

Step-by-step explanation:

Given as :

The total of digits having ones and hundreds = 900

The sum of digits = 18

Let The number of ones digit = O

And The number of hundreds digit = H

So, According to question

H + O = 18             .........1

100 × H + 1 × O = 900          ........2

Solving the equation

( 100 × H - H ) + ( O - O ) = 900 - 18

Or, 99 H + 0 = 882

Or , 99 H = 882

∴   H = \frac{882}{99}

I.e H = 8.9

Put the value of H in eq 1

So, O = 18 - H

I.e  O = 18 - 8.9

∴    O = 9.1

So, number of once = 9.1

number of hundreds = 8.9

Hence The number of once is 9.1  and The number of hundreds is 8.9

Answer

4 0
3 years ago
I already solved this problem. I just need help with the HINT part.
frutty [35]
x+y=25 \\ y=25-x~~Other~number~in~terms~of~x \\ \\ x^2+y^2=313 \\ x^2+2xy+y^2=313+2xy \\ (x+y)^2=313+2x(25-x) \\ \frac{25^2-313}{2} =25x-x^2 \\ x^2-25x+156 \\ \\ \Delta =(-25)^2-4\times 1\times 156 \\ \Delta =625-624 \\ \sqrt{\Delta}=1 \\ \\ x= \frac{25 \pm 1}{2} \\ x= \left \{ {{x_1=13} \atop {x_2=12}} \right.

     The number "x" is given by:
y= \left \{ {{y_1=25-13 \rightarrow~y_1=12} \atop {y_1=25-12 \rightarrow ~y_1=13}} \right.
  
     Therefore, we have:

\boxed {S=({12,13})} \rightarrow~The~curly~braces~does~not~want~appear~here.
8 0
3 years ago
Felix wants to buy some lemonade for the dinner party.
Xelga [282]

Answer:

Yes. Felix is correct.

Step-by-step explanation:

Find out how much ml does a can of lemonade have, I would assume its 330ml since I searched up the ml of a lemonade can.

Find out how much cans of lemonade there are in 2 packs of 8.

2 packs = 8 x 2 = 16 cans of lemonade

Now find out how much ml 16 lemonade cans equal to.

1 can of lemonade = 330ml

16 cans of lemonade = 330 x 16 = 5280ml

Now let's find 5 bottles of 1 litre.

1 litre x 5 = 5 litres.

5280 = 5 litres and 280ml

So Felix is correct about 2 packs of 8 cans is more than 5 bottles of 1 litre.

6 0
3 years ago
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