Answer:
c) 0.932
99% confidence interval for average weights of all packages sold in small meat trays.
(0.932 ,1.071)
Step-by-step explanation:
Explanation:-
Given random sample of 35 packages in small meat trays produced weight with an average of 1.01 lbs. and standard deviation of 0.18 lbs.
size of the sample 'n' = 35
mean of the sample x⁻= 1.01lbs
standard deviation of the sample 'S' = 0.18lbs
<u>The 99% confidence intervals are given by</u>

The degrees of freedom γ=n-1 =35-1=34
tₐ = 2.0322
99% confidence interval for average weights of all packages sold in small meat trays

( 1.01 - 0.06183 , 1.01+0.06183)
(0.932 ,1.071)
<u>Final answer</u>:-
<u>99% confidence interval for average weights of all packages sold in small meat trays.</u>
<u>(0.932 ,1.071)</u>
Answer:
$72
Step-by-step explanation:
Cost of the lunch = $60
Sales tax = 5% of $60
= 5/100 × 60
= 0.05 × 60
= $3
Tip = 15% of $60
= 15/100 × 60
= 0.15 × 60
= $9
how much in total did he pay?
Total amount paid = cost of the lunch + sales tax + tip
= $60 + $3 + $9
= $72
Latrell paid $72 in total for the lunch
Do you need me to simplify ... or what?
Please let me know so I can help you (:
Answer:
im sorry im not going to read all that because i really dont like reading so im sorry :(
Step-by-step explanation: