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Tanya [424]
3 years ago
5

Which of the following is NOT an ethical way of getting to the top of a web search?

Computers and Technology
1 answer:
lakkis [162]3 years ago
5 0

Answer:

C

Explanation:

Changing your search engine's algorithm is basically hacking into the resource code

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Assume that the population of Mexico is 128 million and that the population increases 1.01 percent annually. Assume that the pop
horrorfan [7]

Answer:

//Define class

public class Main {

 //define main method

 public static void main(String[] args)  

 {

   //declare and initialize the double type variable to 128

   double mexico = 128;

   //declare and initialize the double type variable to 323

   double us = 323;

   //declare and initialize the integer type variable to 0  

   int yr = 0;

   //set the while loop to check which is greater

   while (mexico < us)  

   {

     //increment in the variable by 1

     yr++;

     //initialize in the variables acc. to the percentage

     mexico *= 1.0101;

     us *= 0.9985;

   }

   //print the following results

   System.out.println("Population of the Mexico will be exceed the population U.S. in " + yr + " years");

   System.out.println("Population of the Mexico will be " + mexico + " million");

   System.out.println("and population of the U.S. will be " + us + " million");

 }

}

<u>Output</u>:

Population of the Mexico will be exceed the population U.S. in81 years

Population of the Mexico will be 288.88435953355025 million

and population of the U.S. will be 286.0198193927948 million

Explanation:

<u>Following are the description of the program</u>.

  • Firstly, we define the class 'Main' and inside it, we define the main method.
  • Then, declare two double data type variables which are 'mexico' and 'us' and initialize in it to 128 and 323.
  • Declare integer data type variable 'yr' and initialize in it to 0.
  • Set the while loop and pass the condition to check that the variable 'mexico' is less than the variable 'us' then, increment in the variable 'yr' by 1 and multiply the variables 'us' and 'mexico' by the following percentage.
  • Finally, print the following results with the message.
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Scott does not use privacy settings on his social media
likoan [24]

Answer:

ARREST HIM!!!

Explanation:

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3 years ago
Read 2 more answers
Write a Java application with a main() to find the two largest distinct integers entered on the command line by the user. We are
Setler [38]

Answer:

import java.util.Scanner; // Scanner class is to use input output functions

public class TwoDistinctLargest //class to find two distinct largest nos

{

public static void main(String[] args) { //start of main() function

Scanner input = new Scanner(System.in); // creates Scanner type object

       int integers = 0, largest1 = 0, largest2 = 0; // declare variables

/* integers holds the input integer values, largest1 has 1st largest number and largest 2 contains second distinct largest number, i is used as the count variable to move through the input integers */

       int i = 0;  

//prompts user to enter integers and enter 0 to stop

       System.out.println("Enter the integers (press 0 to stop): ");

       integers = input.nextInt(); //reads and scans input integers

       while(integers != 0) {

/* the loop keeps taking integer values from user until the value of integers is equal to 0, this means until the user enters 0 */

//checks if the value of integer is greater than first largest computed number

           if(integers > largest1) {

//if the value in largest1 is greater than that of largest2

               if(largest1 > largest2) {

                   largest2 = largest1; } // then value of largest1 is set to largest2                

               largest1 = integers; // largest1 now holds the value of integers //which means largest1 holds the first distinct largest integer

           } else { //checks if the value of integers is greater than largest2

               if(integers > largest2) {

//if the value of integers is not equal to that of largest1

                   if(integers!=largest1)  {

// set the value of second distinct largest number to largest2

                   largest2 = integers;}              }            }

                     i++; //keeps moving to the next input integer

           integers = input.nextInt();     //keeps taking input integers    }      

//prints the two distinct largest integers

       System.out.println("\n The 1st largest distinct integer is " + largest1);

       System.out.println("\n The 2nd largest distinct integer is " + largest2); } }

Explanation:

Lets suppose the user inputs the following integers

1, 6, 5, 6, 0

Initial values are:

integers = 0

largest1 = 0

largest2 = 0

i = 0

When the user enters 1, then value of integers = 1

while loop checks if integers!=0. As integers =1 so the program enters the body of while loop. The first IF condition is checked if(integers > largest1)

As largest1 = 0 and integers =1 so this condition evaluates to true as 1 > 0

So the statements in the body of this IF condition are executed. This if conditions contains another if statement if(largest1 > largest2) which checks if the value largest1 is greater than that of largest2. Its false because largest1 =0 and largest2 =0 so largest1 = largest2, so the statement of this if condition body will not execute and program moves to this                 largest1 = integers; statement which sets the value of integers i.e. 1 to largest1. So the value of largest1 = 1

Now the i is incremented by 1 and it points at second value of integers= 6.

while loop checks if integers!=0. As integers =6 so the program enters the body of while loop. The first IF condition is checked if(integers > largest1)

As largest1 = 1 and integers =6 so this condition evaluates to true as 6>1

So the statements in the body of this IF condition are executed. This if conditions contains another if statement if(largest1 > largest2) which checks if the value largest1 is greater than that of largest2.

Its true because largest1 =1 and largest2 =0 so largest1 > largest2, so the next statement is executed largest2 = largest1; So now the value of largest2=1.

Now program moves to this largest1 = integers; statement which sets the value of integers i.e. 6 to largest1. So the value of largest1 = 6

Now the i is incremented by 1 and it points at second value of integers= 5.

while loop condition is again true. IF condition is checked if(integers > largest1)

As largest1 = 6 and integers =5 so this condition evaluates to false as 5<6. So this IF part will not execute and program control moves to the else part.

Else part has an if condition if(integers > largest2) which evaluates to true because integers = 5 and largest2 = 1 so the program moves to next if statement inside the previous if statement of else part i.e. if(integers!=largest1). This if statement is the main statement which will help in finding two distinct largest numbers in case the same largest value is input more than once. It checks If the value of integers is not equal to largest1 value. As integers = 5 and  largest1 = 6 so this if condition is true. If this condition is not used in this program then largest2 will not be assigned distinct largest values but assigned 6 for both largest1 and largest2 as 6 is input twice. Next this if statement  largest2 = integers assigns value of integers to largest2 which is the second largest distinct integer.

Now the i is incremented by 1 integers value become 0.

while loop checks if integers!=0. As integers =0 so the while loop breaks. The last two print statements which produce following output.

The 1st largest distinct integer is: 6

The 2nd largest distinct integer is: 5

7 0
3 years ago
Consider a demand-paging system with the following time-measured utilizations: CPU utilization 20% Paging disk 97.7% Other I/O d
Zarrin [17]

Answer:

see explaination please

Explanation:

a. Install a faster CPU. Answer:NO

Optional: a faster CPU reduces the CPU utilizationfurther since the CPU will spend more time waiting for a process toenter in the ready queue.

b. Install a bigger paging disk. Answer:NO

Optional: the size of the paging disk does not affect theamount of memory that is needed to reduce the pagefaults.

c. Increase the degree of multiprogramming Answer:NO

Since each process would have fewer frames available andthe page fault rate would increase

d. Decrease the degree of multiprogramming.Answer: YES

Optional: by suspending some of the processes, the otherprocesses will have more frames in order to bring their pages inthem, hence reducing the page faults.

e. Install more main memory. Answer:Likely

Optional: more pages can remain resident and do notrequire paging to or from the disks.

f. Install a faster hard disk or multiplecontrollers with multiple hard disks. Answer:Likely

(Optional)

g. Add prepaging to the page-fetchalgorithms.Answer: Likely

(Optional.)

h. Increase the page size. Answer:NO

Since each process would have fewer frames available and the page fault rate would increase

5 0
3 years ago
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