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larisa [96]
3 years ago
12

Find the equation of the line perpendicular to y=-2/3x -7 that runs through the points (6,1) in slope intercept form

Mathematics
1 answer:
SVEN [57.7K]3 years ago
7 0

The equation of line is:

y = \frac{3}{2}x-8

Further explanation:

Given equation of line

y=-\frac{2}{3}x-7

Comparing it with the standard form

y = mx + b gives us:

slope = m1 = -2/3

Let m2 be the slope of second line

The product of slopes of two perpendicular lines is -1.

m_1* m_2 = -1\\-\frac{2}{3} *m_2 = -1\\m_2 = -1 * -\frac{3}{2}\\m_2 = \frac{3}{2}\\Putting\ in\ standard\ form\\y = \frac{3}{2}x +b

We have to find the value of b. So, Putting the point(6,1)

1 = \frac{3}{2}(6) +b\\1 = (3 * 3) + b\\1=9+b\\1-9 =b\\b = -8\\The\ final\ equation\ is:\\y= \frac{3}{2}x -8

Keywords: Coordinate geometry, Point-slope form

Learn more about coordinate geometry at:

  • brainly.com/question/2488474
  • brainly.com/question/2601054

#LearnwithBrainly

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Step-by-step explanation:

6 0
2 years ago
Seven balls are randomly withdrawn from an urn that contains 12 red, 16 blue, and 18 green balls. Find the probability that (a)
UNO [17]

Answer:

a) P=0.226

b) P=0.6

c) P=0.0008

d) P=0.74

Step-by-step explanation:

We know that the seven balls are randomly withdrawn from an urn that contains 12 red, 16 blue, and 18 green balls. Therefore, we have 46 balls.

a) We calculate the probability that are 3 red, 2 blue, and 2 green balls.

We calculate the number of possible combinations:

C_7^{46}=\frac{46!}{7!(46-7)!}=53524680

We calculate the number of favorable combinations:

C_3^{12}\cdot C_2^{16}\cdot C_2^{18}=660\cdot 120\cdot 153=12117600

Therefore, the probability is

P=\frac{12117600}{53524680}\\\\P=0.226

b) We calculate the probability that are at least 2 red balls.

We calculate the probability  withdrawn of 1 or none of the red balls.

We calculate the number of possible combinations:

C_7^{46}=\frac{46!}{7!(46-7)!}=53524680

We calculate the number of favorable combinations: for 1 red balls

C_1^{12}\cdot C_7^{34}=12\cdot 1344904=16138848

Therefore, the probability is

P_1=\frac{16138848}{53524680}\\\\P_1=0.3

We calculate the number of favorable combinations: for none red balls

C_7^{34}=5379616

Therefore, the probability is

P_0=\frac{5379616}{53524680}\\\\P_0=0.1

Therefore, the  the probability that are at least 2 red balls is

P=1-P_1-P_0\\\\P=1-0.3-0.1\\\\P=0.6

c) We calculate the probability that are all withdrawn balls are the same color.

We calculate the number of possible combinations:

C_7^{46}=\frac{46!}{7!(46-7)!}=53524680

We calculate the number of favorable combinations:

C_7^{12}+C_7^{16}+C_7^{18}=792+11440+31824=44056

Therefore, the probability is

P=\frac{44056}{53524680}\\\\P=0.0008

d) We calculate the probability that are either exactly 3 red balls or exactly 3 blue balls are withdrawn.

Let X, event that exactly 3 red balls selected.

P(X)=\frac{C_3^{12}\cdot C_4^{34}}{53524680}=0.57\\

Let Y, event that exactly 3 blue balls selected.

P(Y)=\frac{C_3^{16}\cdot C_4^{30}}{53524680}=0.29\\

We have

P(X\cap Y)=\frac{18\cdot C_3^{12} C_3^{16}}{53524680}=0.12

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P(X\cup Y)=P(X)+P(Y)-P(X\cap Y)\\\\P(X\cup Y)=0.57+0.29-0.12\\\\P(X\cup Y)=0.74

8 0
3 years ago
Peter is giving marbles to some children at a carnival. He has 5 red marbles, 4 blue marbles, and 3 yellow marbles. If Peter sel
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D.

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(-6,-1) to (-6, 1) :)
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Lesechka [4]

9514 1404 393

Answer:

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