What is 3/4 ×4= what plz help plzzzzzzz

2767545 to the nearest ten

vovangra [49]

276550 hope this helps !

5 0

4 years ago

Read 2 more answers

1. 10:15 H Wednesday (Philippines) - 05:15 H Wednesday (Riyadh, Saudi<br>Arabia)<br>Time difference

kotegsom [21]

Answer:

5hours

Step-by-step explanation:

10:15 - 05:15 = 5 hours

Thsi means that local time in Philippines is 5 hours ahead of local time in Riyadh, Saudi Arabia.

The time can be interpreted as follows ; At a certain time in the Philippines, say 10:15 am in the morning, At this verh point in the Riyadh, Saudi Arabia, the time will be :

(10:15 - 5 hours) = 05:15

7 0

3 years ago

Mary's SUV has a 15-gallon gas tank. The SUV gets an estimated 24 miles per gallon.

Delvig [45]

Answer:

A = 360

B= 180

C=270

Step-by-step explanation:

5 0

3 years ago

Over which interval is the graph of the parent absolute value function decreasing?

Artemon [7]

I think the answer is b

6 0

3 years ago

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Clarinex is a drug used to treat asthma. In clinical tests of this drug, 1655 patients were treated with 5- mg doses of Clarinex

bagirrra123 [75]

Answer:

$z=\frac{0.021 -0.012}{\sqrt{\frac{0.012(1-0.012)}{1655}}}=3.363$

$p_v =P(z>3.363)=0.00039$

So the p value obtained was a very low value and using the significance level given $\alpha=0.01$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 1% of significance the proportion of interest is significantly higher than 0.012 (1.2%)

Step-by-step explanation:

Data given and notation

n=1655 represent the random sample taken

$\hat p=0.021$ estimated proportion of interest

$p_o=0.012$ is the value that we want to test

$\alpha=0.01$ represent the significance level

Confidence=99% or 0.99

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that true proportions is higher than 0.012.:

Null hypothesis: $p \leq 0.012$

Alternative hypothesis: $p > 0.012$

When we conduct a proportion test we need to use the z statisitic, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.021 -0.012}{\sqrt{\frac{0.012(1-0.012)}{1655}}}=3.363$

Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The significance level provided $\alpha=0.01$ . The next step would be calculate the p value for this test.

Since is a right tailed test the p value would be:

$p_v =P(z>3.363)=0.00039$

So the p value obtained was a very low value and using the significance level given $\alpha=0.01$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 1% of significance the proportion of interest is significantly higher than 0.012 (1.2%)

3 0

3 years ago