Answer:
d = 234.6 m
Step-by-step explanation:
You can consider a system of coordinates with its origin at the beginning of the walk of the student.
When she start to walk, she is at (0,0)m. After her first walk, her coordinates are calculated by using the information about the incline and the distance that she traveled:

she is at the coordinates (52.97 , 28.16)m.
Next, when she walks 180m to the east, her coordinates are:
(52.97+180 , 28.16)m = (232.97 , 28.16)m
To calculate the distance from the final point of the student to the starting point you use the Pythagoras generalization for the distance between two points:

The displacement of the student on her complete trajectory was of 234.6m
The first thing I did was to be a part of the world, and the other is a great way to get the best out of the way, and I have to say that I am not a fan of the
The first thing I did was to be apart part of the problem and a few of my own personal information ℹ️ and a
Answer:
0.45 = 45% probability that the member uses the golf course but not the tennis courts
Step-by-step explanation:
I am going to solve this question using the events as Venn sets.
I am going to say that:
Event A: Uses the golf courses.
Event B: Uses the tennis courts.
5% use neither of these facilities.
This means that 
75% use the golf course, 50% use the tennis courts
This means, respectively, by:

Probability that a member uses both:
This is
. We have that:

So

What is the probability that the member uses the golf course but not the tennis courts?
This is
, which is given by:

So

0.45 = 45% probability that the member uses the golf course but not the tennis courts
Answer:
24cm
Step-by-step explanation:
6+6+6+6=24
12 is half so you should add 12 or multiply by 2