Question

Question 3 options:

Answer 1

Answer:

Hence, the coordinates of A',B' and C' are:

A' (68,-102)

B' (-136,102)

C' (68,102)

Step-by-step explanation:

We are given a Triangle ABC such that:

The vertex of the triangle are given as:

A (-2, 3)

B (4, -3)

C (-2, -3)

Now it is given that:

The triangle ABC has been dilated to form triangle A'B'C'  with a scale factor of -34.

This means that:

A → A'

B → B'

and C → C'

We are asked to find the coordinates points for triangle A'B'C'.

We know that if there is a dilation with some scale factor 'k' then the coordinates of the transformed image get multiplied by the same scale factor.

i.e. coordinates of A'=(-34×(-2),(-34)×3)=(68,-102)

coordinates of B'=(-34×4,(-34)×(-3))=(-136,102)

and coordinates of C'=(-34×(-2),-34×(-3))=(68,102)

Hence, A (-2,3) → A' (68,-102)

B (4,-3) → B' (-136,102)

C (-2,-3) → C' (68,102)