Answer:
Hence, the coordinates of A',B' and C' are:
A' (68,-102)
B' (-136,102)
C' (68,102)
Step-by-step explanation:
We are given a Triangle ABC such that:
The vertex of the triangle are given as:
A (-2, 3)
B (4, -3)
C (-2, -3)
Now it is given that:
The triangle ABC has been dilated to form triangle A'B'C' with a scale factor of -34.
This means that:
A → A'
B → B'
and C → C'
We are asked to find the coordinates points for triangle A'B'C'.
We know that if there is a dilation with some scale factor 'k' then the coordinates of the transformed image get multiplied by the same scale factor.
i.e. coordinates of A'=(-34×(-2),(-34)×3)=(68,-102)
coordinates of B'=(-34×4,(-34)×(-3))=(-136,102)
and coordinates of C'=(-34×(-2),-34×(-3))=(68,102)
Hence, A (-2,3) → A' (68,-102)
B (4,-3) → B' (-136,102)
C (-2,-3) → C' (68,102)
